问:如何正确使用moveToThread(this)？

Question

我有一个这样的课:

class myClass:public QThread

然后在我的构造函数中我做了:

myClass::myClass(){
    moveToThread(this);
    ...
}

似乎所有成员槽实际上都在工作线程上工作.但是在这种情况下如何在解构过程中阻止线程？

Answer 1

根本就不要那样做线程.

moveToThread()Qt文档中描述了正确的使用方法:

class Worker : public QObject
{
    Q_OBJECT

public slots:
    void doWork(const QString &parameter) {
        QString result;
        /* ... here is the expensive or blocking operation ... */
        emit resultReady(result);
    }

signals:
    void resultReady(const QString &result);
};

class Controller : public QObject
{
    Q_OBJECT
    QThread workerThread;
public:
    Controller() {
        Worker *worker = new Worker;
        worker->moveToThread(&workerThread);
        connect(&workerThread, &QThread::finished, worker, &QObject::deleteLater);
        connect(this, &Controller::operate, worker, &Worker::doWork);
        connect(worker, &Worker::resultReady, this, &Controller::handleResults);
        workerThread.start();
    }
    ~Controller() {
        workerThread.quit();
        workerThread.wait();
    }
public slots:
    void handleResults(const QString &);
signals:
    void operate(const QString &);
};

或通过继承QThread,如:

class WorkerThread : public QThread
{
    Q_OBJECT
    void run() Q_DECL_OVERRIDE {
        QString result;
        /* ... here is the expensive or blocking operation ... */
        emit resultReady(result);
    }
signals:
    void resultReady(const QString &s);
};

void MyObject::startWorkInAThread()
{
    WorkerThread *workerThread = new WorkerThread(this);
    connect(workerThread, &WorkerThread::resultReady, this, &MyObject::handleResults);
    connect(workerThread, &WorkerThread::finished, workerThread, &QObject::deleteLater);
    workerThread->start();
}

但不是两个在同一时间.更多关于该主题的信息