youtube.subscriptions.list(api v3) - nextPageToken不可用

Fle*_*hen 6 javascript java youtube api subscriptions

我正试图从订阅中获取所有频道.但是"nextPageToken"不可用.

响应应该包含"nextPageToken":

(来自developers.google.com - YouTube(v3) - 订阅:列表)

{
  "kind": "youtube#subscriptionListResponse",
  "etag": etag,
  "nextPageToken": string,
  "prevPageToken": string,
  "pageInfo": {
  "totalResults": integer,
  "resultsPerPage": integer
  },
  "items": [
    subscription Resource
  ]
}
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这是我的要求:

GET https://www.googleapis.com/youtube/v3/subscriptions?part=snippet&maxResults=10&mine=true&key={YOUR_API_KEY}
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API Explorer - YouTube(v3) - Subscriptions.list:

https://developers.google.com/apis-explorer/#p/youtube/v3/youtube.subscriptions.list?part=snippet&maxResults=10&mine=true

我的回复:

{
 "kind": "youtube#subscriptionListResponse",
 "etag": "\"XXXXX/XXXXX\"",
 "pageInfo": {
  "totalResults": 115,
  "resultsPerPage": 10
 },
 "items": [
  ...
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你能告诉我为什么nextPageToken丢失了吗?

小智 6

这是我想出的一个 JS 片段,用于生成至少 1024 个 pageToken,我不能保证它会产生任何超出此范围的有效内容,因为我找不到任何服务可以为我提供偏移量 > 450 的令牌来验证我的猜测和假设。

var d0 = "AEIMQUYcgkosw048";
var d1 = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
var d2 = d1;
var d1c = 0;
var d2c = 0;
var overflowSuffix = "Q";
var direction = "AA";
var d2OverflowCounter = 0;
var pageSize = 50;

for (i = 0; i < 1024; i++) {
  if (i % pageSize == 0) console.log("C" + d1.charAt((d1c / d0.length) % d1.length) + d0.charAt(i % d0.length) + overflowSuffix + direction, ":", i);
  if (++d1c % (1 << 8) == 0) d1c = 1 << 7;
  if (++d2c % (1 << 7) == 0) overflowSuffix = d2.charAt(++d2OverflowCounter) + "E";
}
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(检查开发者工具/控制台以查看生成的代码)


Ale*_*ica 5

我现在有一个解决方法.请告诉我这是否有帮助.

对于其他API Youtube V3 API调用的每个页面,令牌似乎是相同的,因此我可以使用它来获取我需要的所有订阅页面.

tokens = ['CDIQAA','CGQQAA','CJYBEAA','CMgBEAA','CPoBEAA','CKwCEAA','CN4CEAA','CJADEAA','CMIDEAA','CPQDEAA','CKYEEAA', ...]
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如果您需要更多,可以使用另一个Youtube API获取更多页面令牌.只需一次获取1个元素并记录要在此API中使用的标记.

我只需知道何时停止...所以我检查API调用何时没有返回通道!

@retry(stop_max_attempt_number=7)    
def get_subscription_page(self, channel_id, pageToken):        
    print 'Retrieving subscription page using Youtube API (token: %s)' % pageToken
    res = self.youtube_data_api.subscriptions().list(part="id,snippet,contentDetails",channelId=channel_id, maxResults=50, pageToken=pageToken).execute()
    return res


def get_subscriptions(self, channel_id):
    self.authorize(channel_id)                       
    subs = []         

    # Tokens to deal with api bug...
    # https://code.google.com/p/gdata-issues/issues/detail?id=7163
    tokens = ['CDIQAA','CGQQAA','CJYBEAA','CMgBEAA','CPoBEAA','CKwCEAA','CN4CEAA','CJADEAA','CMIDEAA','CPQDEAA','CKYEEAA']

    iPage = 0
    pageToken = ''        
    while True:            

        res = self.get_subscription_page(channel_id, pageToken)            

        channelIds = []
        for channel in res['items']: channelIds.append(channel.get('snippet').get('resourceId').get('channelId'))
        pageToken = res.get('nextPageToken')

        # If no next page token is returned... it might be caused by a bug.
        # This workaroud will only have effect when the bug still lives.
        if not pageToken:
            if not channelIds:
                # Workaroud for this: https://code.google.com/p/gdata-issues/issues/detail?id=7163
                print ' (Workaround due to API bug) No channels returned in this API call! Finished!'
                break
            else:
                pageToken = tokens[iPage]

        # get channel info for each channel ID
        channelsInfo = self.get_channel_info(channelIds)            
        subs += channelsInfo
        print ' Itens already retrieved: %d ' % len(subs)                                                            
        iPage += 1

        if args.debug: break
        if pageToken: continue

        print 'No more pages to retrieve!'
        break                

    return subs
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  • 一个警告,令牌取决于maxResults设置.当我将maxResults设置为1并且当它设置为50时,我得到了完全不同的令牌. (2认同)