Laravel DB :: raw使用SELECT列AS"示例名称"

Question

我在尝试使用DB::rawLaravel查询时遇到了一个问题.当我尝试遍历我的结果集时,我无法定位某个列,因为它的名称包含一个空格:

$result = DB::connection("example")->select(DB::raw(
  "SELECT table.column_1 AS 'NameOne',
  table.column_2 AS 'Name Two'
  FROM example;"
));

如您所见,NameOne不包含空格,但Name Two确实如此.循环遍历结果集时,我无法回显结果table.column_2 AS 'Name Two,因为我无法正确定位它.我尝试过的:

<!-- language: html -->
@foreach($result AS $item)
<tr>
  <td>{!! $result->NameOne !!}</td> <!-- Works Fine -->
  <td>{!! $result->Name Two !!}</td> <!-- Doesn't work (obvious syntax error) -->
  <td>{!! $result->Name_Two !!}</td> <!-- Doesn't work (undefined property) -->
  <td>{!! $result->Name+Two !!}</td> <!-- Doesn't work (undefined property) -->
  <td>{!! $result->NameTwo !!}</td> <!-- Doesn't work (undefined property) -->
</tr>
@endforeach

具体来说,未定义的属性错误是:

未定义的属性:stdClass :: $ Name_Two(查看:/var/www/html/APPNAME/resources/views/index.blade.php)

我不想更改密钥,因为这些结果将导出到Excel,我想保留列名称.牢记这一点,我将如何回应这些结果？

另外,输出为dd($results):

array:1 [?
  0 => {#179 ?
    +"NameOne": "NameOne"
    +"Name Two": "NameTwo"
  }
]

Answer 1

你可以用

<td>{!! $result->{'Name Two'} !!}</td>