我有一些代码如下.
MyRequests.cors_request("POST",
APP_CONFIG.APP_URL+"/users/selectAllUsers",
null,
function ok(users) {
$scope.usersNotFiltered = users;
console.log('users--->', users);
console.log('$scope.userPerSystem--->', $scope.userPerSystem);
// delete the items that is already exists in the userPerSystem
function filterUsers(element, index, array) {
console.log("$scope.usersNotFiltered :: " + users);
commonFindAndRemove($scope.usersNotFiltered, 'userId', element.userId);
console.log('a[' + index + '] = ' + element.userId);
}
$scope.userPerSystem.forEach(filterUsers);
$scope.users = $scope.usersNotFiltered;
},
Run Code Online (Sandbox Code Playgroud)
我运行代码并观看控制台.chrome控制台中'[Object]'和'[object Object]'有什么区别?
用户---> [对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象,对象]
$ scope.userPerSystem ---> [Object] 0:Objectlength:1__proto __:Array [0] redca-ias.concat.js:5258
$ scope.usersNotFiltered :: [object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object] ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
第一个日志显示结构,即结构的实时表示,第二个日志是结构的字符串表示.
> var arr = [{}, {}, {}];
> arr // simply logs the object as it is
> [Object, Object, Object]
> arr + '' // converts the structure into string
> "[object Object],[object Object],[object Object]"
Run Code Online (Sandbox Code Playgroud)
当您将字符串与对象连接时,您会得到此结果:
"$scope.usersNotFiltered :: " + users
Run Code Online (Sandbox Code Playgroud)
在上面的代码片段中,JavaScript将结构转换为字符串(原始值)和对象的字符串表示形式[object Object].由于结构是一个对象数组,因此每个元素的字符串表示形式都是连接在一起的,.通过调用Array.prototype.toString()或Array.prototype.join()方法得到类似的结果 :
> var arr = [1, 2, 3];
> arr.toString()
> "1,2,3"
> var arrayOfObjects = [{}, {}, {}];
> arrayOfObjects.toString()
> "[object Object],[object Object],[object Object]"
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
752 次 |
| 最近记录: |