我有2张桌子
A
+----+-------+
| Id | User |
+----+-------+
| 1 | user1 |
| 2 | user2 |
| 3 | user3 |
+----+-------+
B
+----+--------+------+
| Id | UserId | Type |
+----+--------+------+
| 1 | 1 | A |
| 2 | 1 | B |
| 3 | 1 | C |
| 4 | 2 | A |
| 5 | 2 | B |
| 6 | 2 | C |
| 7 | 3 | A |
| 8 | 3 | C |
+----+--------+------+
UserId is FK from table A.Id
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我正在尝试使用单个SQL查询来计算每种类型和类型排列,如下所示.(例如,计数A ^ B表示具有类型A和B的用户数)
+---------+---------+---------+-----------+-----------+-----------+-------------+
| Count A | Count B | Count C | Count A^B | Count A^C | Count B^C | Count A^B^C |
+---------+---------+---------+-----------+-----------+-----------+-------------+
| 3 | 2 | 3 | 2 | 3 | 2 | 2 |
+---------+---------+---------+-----------+-----------+-----------+-------------+
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或者对每个排列计数单独查询.
我尝试在下面查询分别计算A和B类型,但它不起作用.
SELECT count(b1.type) AS count_a, count(b2.type) AS count_b FROM A
JOIN B on A.id = B.user_id
WHERE b1.type = 'A' or b2.type = 'B'
GROUP BY A.id;
+---------+---------+
| Count A | Count B |
+---------+---------+
| 3 | 2 |
+---------+---------+
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你可以写:
select count(case when "Types" @> array['A'] then 1 end) as "COUNT A",
count(case when "Types" @> array['B'] then 1 end) as "COUNT B",
count(case when "Types" @> array['C'] then 1 end) as "COUNT C",
count(case when "Types" @> array['A','B'] then 1 end) as "COUNT A^B",
count(case when "Types" @> array['A','C'] then 1 end) as "COUNT A^C",
count(case when "Types" @> array['B','C'] then 1 end) as "COUNT B^C",
count(case when "Types" @> array['A','B','C'] then 1 end) as "COUNT A^B^C"
from ( select array_agg("Type"::text) as "Types"
from "B"
group by "UserId"
) t
;
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我们的想法是,首先我们使用一个子查询,为每个用户生成一个包含他/她类型的数组; 然后外部查询只计算包含每组类型的数组.
您可以在http://sqlfiddle.com/#!15/cbb45/1上看到它的实际效果.(我还在其中包含了子查询的修改版本,以帮助您了解它是如何工作的.)
一些相关的PostreSQL文档:
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