比较日期时间与Doctrine之间的日期

Question

我有一个Syfmony2应用程序,其中包含一个具有日期字段的表.此日期字段是DateTime类型.

我需要获得与现在相同的所有实体.

但如果我这样做:

$now = new \DateTime();
$data = $entityRepository->findByDate($now);

我得到0结果,因为Doctrine正在比较DateTime对象,我需要只比较年,月和日,而不是小时...只有de Date对象,而不是DateTime.

任何的想法？感谢:D

Answer 1

我看到这个简单的方法:

$now = new \DateTime();

$data = $entityRepository->getByDate($now);

然后在你的存储库中

public function getByDate(\Datetime $date)
{
    $from = new \DateTime($date->format("Y-m-d")." 00:00:00");
    $to   = new \DateTime($date->format("Y-m-d")." 23:59:59");

    $qb = $this->createQueryBuilder("e");
    $qb
        ->andWhere('e.date BETWEEN :from AND :to')
        ->setParameter('from', $from )
        ->setParameter('to', $to)
    ;
    $result = $qb->getQuery()->getResult();

    return $result;
}

Answer 2

存储库中的方法

public function getDays(\DateTime $firstDateTime, \DateTime $lastDateTime)
{
    $qb = $this->getEntityManager()->createQueryBuilder()
        ->select('c')
        ->from('ProjectBundle:Calendar', 'c')
        ->where('c.date BETWEEN :firstDate AND :lastDate')
        ->setParameter('firstDate', $firstDateTime)
        ->setParameter('lastDate', $lastDateTime)
    ;

    $result = $qb->getQuery()->getResult();

    return $result;
}

和行动

public function calendarAction()
{
    $currentMonthDateTime = new \DateTime();
    $firstDateTime = $currentMonthDateTime->modify('first day of this month');
    $currentMonthDateTime = new \DateTime();
    $lastDateTime = $currentMonthDateTime->modify('last day of this month');

    $days = $this->getDoctrine()
        ->getRepository('ProjectBundle:Calendar')
        ->getDays($firstDateTime, $lastDateTime);

    return ['days' => $days];
}