use*_*094 7 python orm sqlalchemy
我知道你可以通过提供**kwargs来为SQLAlchemy的查询构建动态过滤器filter_by.
例如
filters = {'id': '123456', 'amount': '232'}
db.session.query(Transaction).filter_by(**filters)
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以下是我的问题:
如果我需要通过"大于"或"小于"条款查询,该怎么办?例如(原始SQL):
select * from transaction t
where t.amount > 10 and t.amount < 100;
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Wol*_*lph 17
它不是使用filter_by我建议使用filter,它为您提供了更多选择.
例如(来自手册):
db.session.query(MyClass).filter(
MyClass.name == 'some name',
MyClass.id > 5,
)
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就你的情况而言:
filters = (
Transaction.amount > 10,
Transaction.amount < 100,
)
db.session.query(Transaction).filter(*filters)
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小智 7
def get_filter_by_args(dic_args: dict):
filters = []
for key, value in dic_args.items(): # type: str, any
if key.endswith('___min'):
key = key[:-6]
filters.append(getattr(model_class, key) > value)
elif key.endswith('___max'):
key = key[:-6]
filters.append(getattr(model_class, key) < value)
elif key.endswith('__min'):
key = key[:-5]
filters.append(getattr(model_class, key) >= value)
elif key.endswith('__max'):
key = key[:-5]
filters.append(getattr(model_class, key) <= value)
else:
filters.append(getattr(model_class, key) == value)
return filters
dic_args = {
'is_created': 1,
'create_time__min': 1588125484029,
}
filters = get_filter_by_args(dic_args)
lst = session.query(model_class).filter(*filters)
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