SQLALchemy动态filter_by

use*_*094 7 python orm sqlalchemy

我知道你可以通过提供**kwargs来为SQLAlchemy的查询构建动态过滤器filter_by.

例如

    filters = {'id': '123456', 'amount': '232'}
    db.session.query(Transaction).filter_by(**filters)
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以下是我的问题:

如果我需要通过"大于"或"小于"条款查询,该怎么办?例如(原始SQL):

 select * from transaction t 
 where t.amount > 10 and t.amount < 100;
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Wol*_*lph 17

它不是使用filter_by我建议使用filter,它为您提供了更多选择.

例如(来自手册):

db.session.query(MyClass).filter(
    MyClass.name == 'some name',
    MyClass.id > 5,
)
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就你的情况而言:

filters = (
    Transaction.amount > 10,
    Transaction.amount < 100,
)
db.session.query(Transaction).filter(*filters)
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  • @JavaSa所有运算符都可以通过Python中的[operator](https://docs.python.org/3/library/operator.html)模块获得.因此,您也可以使用`operator.ge(a,b)`而不是`a> = b` (3认同)

小智 7

def get_filter_by_args(dic_args: dict):
    filters = []
    for key, value in dic_args.items():  # type: str, any
        if key.endswith('___min'):
            key = key[:-6]
            filters.append(getattr(model_class, key) > value)
        elif key.endswith('___max'):
            key = key[:-6]
            filters.append(getattr(model_class, key) < value)
        elif key.endswith('__min'):
            key = key[:-5]
            filters.append(getattr(model_class, key) >= value)
        elif key.endswith('__max'):
            key = key[:-5]
            filters.append(getattr(model_class, key) <= value)
        else:
            filters.append(getattr(model_class, key) == value)
    return filters

dic_args = {
    'is_created': 1,
    'create_time__min': 1588125484029,
}
filters = get_filter_by_args(dic_args)
lst = session.query(model_class).filter(*filters)
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