我尝试使用Eigen库来创建样条曲线.但是,一旦我创建样条曲线,我就不知道如何得到给定点x的值.
请参阅下面的示例,并解释我的意图:
#include <Eigen/Core>
#include <unsupported/Eigen/Splines>
int main(int argc, char const* argv[])
{
// points at (0,0) (15,12) and (30,17)
Eigen::MatrixXd points(2, 3);
points << 0, 15, 30,
0, 12, 17;
typedef Eigen::Spline<double, 2> spline2d;
spline2d s = Eigen::SplineFitting<spline2d>::Interpolate(points, 2);
// I now have a spline called s.
// I want to do something like:
double x = 12.34;
double new_y = s(x)[1]; // However this s() function uses a chord value. What is a chord value?
// Is there a:
double new_y2 = s.eval(x)
}
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Win*_*ute 11
我知道这可能会让人感到困惑.当您使用Eigen Spline拟合模块时,它不会对函数R - > R进行建模.例如,您可以使用它构建螺旋线.这意味着你不能期望从X值获得Y值,而是在样条曲线上选择它们沿着样条曲线的距离(因此是弦长).
可以使用模块对函数建模,虽然不是非常直观:考虑你的Y值在R 1中,而不是让Eigen计算弦长,而是提供你自己的一组结点参数,它们的间距就像你的X值一样(缩小到[0,1],因此算法可以应对).它可以打包这样的东西:
#include <Eigen/Core>
#include <unsupported/Eigen/Splines>
#include <iostream>
class SplineFunction {
public:
SplineFunction(Eigen::VectorXd const &x_vec,
Eigen::VectorXd const &y_vec)
: x_min(x_vec.minCoeff()),
x_max(x_vec.maxCoeff()),
// Spline fitting here. X values are scaled down to [0, 1] for this.
spline_(Eigen::SplineFitting<Eigen::Spline<double, 1>>::Interpolate(
y_vec.transpose(),
// No more than cubic spline, but accept short vectors.
std::min<int>(x_vec.rows() - 1, 3),
scaled_values(x_vec)))
{ }
double operator()(double x) const {
// x values need to be scaled down in extraction as well.
return spline_(scaled_value(x))(0);
}
private:
// Helpers to scale X values down to [0, 1]
double scaled_value(double x) const {
return (x - x_min) / (x_max - x_min);
}
Eigen::RowVectorXd scaled_values(Eigen::VectorXd const &x_vec) const {
return x_vec.unaryExpr([this](double x) { return scaled_value(x); }).transpose();
}
double x_min;
double x_max;
// Spline of one-dimensional "points."
Eigen::Spline<double, 1> spline_;
};
int main(int argc, char const* argv[])
{
Eigen::VectorXd xvals(3);
Eigen::VectorXd yvals(xvals.rows());
xvals << 0, 15, 30;
yvals << 0, 12, 17;
SplineFunction s(xvals, yvals);
std::cout << s(12.34) << std::endl;
}
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