use*_*153 16 javascript php session codeigniter
参考本教程.使用php跟踪上传进度.我想让它在Codeigniter中运行.我没有意识到开始让它在CI中发挥作用.我想上传文件并跟踪进度.
<?php $arr = array("id"=>"myform");
echo form_open_multipart("welcome/uploads",$arr); ?>
<input type="hidden" value="myForm" name="<?php echo ini_get("session.upload_progress.name"); ?>">
<table>
<tr>
<td>file</td>
<td><input type="file" name="images[]" multiple></td>
</tr>
<tr>
<td>name</td>
<td><input type="text" name="naam"></td>
</tr>
<tr>
<td></td>
<td><input type="submit"></td>
</tr>
</table>
<?php echo form_close(); ?>
<div id="bar_blank">
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function toggleBarVisibility() {
var e = document.getElementById("bar_blank");
e.style.display = (e.style.display == "block") ? "none" : "block";
}
function createRequestObject() {
var http;
if (navigator.appName == "Microsoft Internet Explorer") {
http = new ActiveXObject("Microsoft.XMLHTTP");
}
else {
http = new XMLHttpRequest();
}
return http;
}
function sendRequest() {
var http = createRequestObject();
http.open("GET", "<?php echo base_url().'index.php/welcome/progress' ?>");
http.onreadystatechange = function () { handleResponse(http); };
http.send(null);
}
function handleResponse(http) {
var response;
if (http.readyState == 4) {
response = http.responseText;
document.getElementById("bar_color").style.width = response + "%";
document.getElementById("status").innerHTML = response + "%";
if (response < 100) {
setTimeout("sendRequest()", 1000);
}
else {
toggleBarVisibility();
document.getElementById("status").innerHTML = "Done.";
}
}
}
function startUpload() {
toggleBarVisibility();
setTimeout("sendRequest()", 1000);
}
(function () {
document.getElementById("myForm").onsubmit = startUpload; //error is here
})();
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根据上面的教程,它在核心php.向控制器提交表单CI请求时dashboard/addRoom,我的页面无论如何都会刷新.但是在教程中,Form重定向到PHP_SELF(相同的php文件).我对它没有任何想法.请帮我.
function progress()
{
session_start();
$key = ini_get("session.upload_progress.prefix") . "myForm";
if (!empty($_SESSION[$key])) {
$current = $_SESSION[$key]["bytes_processed"];
$total = $_SESSION[$key]["content_length"];
echo $current < $total ? ceil($current / $total * 100) : 100;
}
else {
echo 100;
}
}
public function uploads()
{
if(!empty($_FILES['images']['name'][0]))
{
//uploadinf file code
}
}
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如果你只想用jQuery做,那么我已经使用了jQuery Form Submit Plugin,它将为你提供进展等等.正如您在评论中所说,您不需要任何插件,然后按照这些步骤操作,并按照教程建议实施.
让我们假设您有控制器仪表板,并且方法addRoom显示您的html表单:
class Dashboard extends CI_Controller {
function addRoom() {
// Detect URI: http://example.com/dashboard/addRoom/upload_file
$upload_req = $this->uri->segment("3");
if( $upload_req == "upload_file" ) {
// Do the file upload Actions
}
// Generate Form
$this->load->view("Generate_view");
}
}
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视图:
<?php
$ar = array("class"=>"form-horizontal");
echo form_open_multipart('dashboard/addRoom/upload_file',$ar);
?>
<input type="text" name="fileName">
<input type="file" name="upload">
<input type="submit" value="add">
<?php echo form_close(); ?>
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在这种情况下,即使您提交或不提交,您的表单仍然在同一个控制器和方法上.
更新:根据更新的答案,请使用codeigniter默认库进行会话和文件上传,如果出现JS错误,请使用控制台选项卡(Chrome)调试错误,或者如果您使用的是firefox,则使用firebug扩展来调试Javascript.
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