Ste*_*sky 4 json scala playframework-2.0
在我的build.sbt:
lazy val commonSettings = Seq(
version := "1.0.0",
scalaVersion := "2.11.6"
)
lazy val root = (project in file(".")).
settings(commonSettings: _*).
settings(
name := "myapp",
libraryDependencies ++= Seq(
"com.typesafe.play" % "play-json_2.11" % "2.3.4",
"org.scalatest" % "scalatest_2.11" % "2.2.4" % "test",
"junit" % "junit" % "4.12" % "test"
)
)
resolvers ++= Seq("Typesafe Repo" at "http://repo.typesafe.com/typesafe/releases/")
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它汇编得很好.现在我使用的代码,import play.api.libs.json._但编译器给出错误说"找不到:对象播放".显然我没有安装游戏.是否可以在play-json不安装Play的情况下使用库?
考虑这个简单的sbt项目:
build.sbt
libraryDependencies ++= Seq(
"com.typesafe.play" %% "play-json" % "2.3.4"
)
resolvers ++= Seq("Typesafe Repo" at "http://repo.typesafe.com/typesafe/releases/")
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然后你可以运行:
sbt console
import play.api.libs.json._
Json.parse("{}")
> res0: play.api.libs.json.JsValue = {}
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是的,你可以玩没有Play的play-json.如果它在您的项目中不起作用,请尝试重新启动SBT或在SBT中执行清理,重新加载,更新和编译.
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