将列汇总到SQL中的当前行？

Question

我正在尝试将列添加到当前行(在SQL Server中).我该怎么做呢？

select t1.CounterTime,
       t1.StartTime,
       t1.EndTime,
       isNull(t1.value, 0) as value1,

       -- How do I make Total1 the sum of t1.value over all previous rows?
       sum( isNull(t1.value, 0) ) over (partition by t1.CounterTime order by t1.CounterTime) as Total1

from   SomeTable t1
order by t1.CounterTime

但我partition by弄错了......

?????????????????????????????????????????????????????????????????????????????????????????????????????
?   ?      CounterTime        ?        StartTime        ?         EndTime         ? value1 ? Total1 ?
?????????????????????????????????????????????????????????????????????????????????????????????????????
? 1 ? 2015-03-17 12:00:00.000 ? 2015-03-17 00:00:00.000 ? 2015-03-18 00:00:00.000 ?     0  ?     0  ?
? 2 ? 2015-03-18 12:00:00.000 ? 2015-03-18 00:00:00.000 ? 2015-03-19 00:00:00.000 ?     0  ?     0  ?
? 3 ? 2015-03-19 12:00:00.000 ? 2015-03-19 00:00:00.000 ? 2015-03-20 00:00:00.000 ?   422  ?   422  ?
? 4 ? 2015-03-20 12:00:00.000 ? 2015-03-20 00:00:00.000 ? 2015-03-21 00:00:00.000 ?   989  ?   989  ?
? 5 ? 2015-03-21 12:00:00.000 ? 2015-03-21 00:00:00.000 ? 2015-03-22 00:00:00.000 ?  1162  ?  1162  ?
? 6 ? 2015-03-22 12:00:00.000 ? 2015-03-22 00:00:00.000 ? 2015-03-23 00:00:00.000 ?   524  ?   524  ?
?????????????????????????????????????????????????????????????????????????????????????????????????????

应该:

??????????
? Total1 ?
??????????
?     0  ?
?     0  ?
?   422  ?
?  1411  ?
?  2573  ?
?  3097  ?
??????????

Answer 1

试试这个
删除"分区依据"只使用"order by"

select t1.CounterTime,
           t1.StartTime,
           t1.EndTime,
           isNull(t1.value, 0) as value1,

           -- How do I make Total1 the sum of t1.value over all previous rows?
           sum( isNull(t1.value, 0) ) over (order by t1.CounterTime) as Total1

    from   SomeTable t1
    order by t1.CounterTime