我有以下模式和字符串的注册匹配问题.模式基本上是一个名称,后跟任意数量的字符,后跟一个短语(见下面的模式),后跟任意数量的字符,后跟机构名称.
pattern = "[David Maxwell|David|Maxwell] .* [educated at|graduated from|attended|studied at|graduate of] .* Eton College"
str = "David Maxwell was educated at Eton College, where he was a King's Scholar and Captain of Boats, and at Cambridge University where he rowed in the winning Cambridge boat in the 1971 and 1972 Boat Races."
match = re.search(pattern, str)
但搜索方法返回上述str的不匹配？我的注册表适合吗？我是reg-ex的新手.任何帮助表示赞赏
[...]表示"来自这组字符的任何字符".如果你想要"这组单词中的任何单词",你需要使用括号:(...|...).
您的表达式中存在另一个问题,即.*(空格,点,星号,空格),这意味着"空格,后跟零个或多个字符,后跟空格".换句话说,最短的匹配是两个空格.但是,您的文本在"educated at"和"Eton College"之间只有一个空格.
>>> pattern = '(David Maxwell|David|Maxwell).*(educated at|graduated from|attended|studied at|graduate of).*Eton College'
>>> str = "David Maxwell was educated at Eton College, where he was a King's Scholar and Captain of Boats, and at Cambridge University where he rowed in the winning Cambridge boat in the 1971 and 1972 Boat Races."
>>> re.search(pattern, str)
<_sre.SRE_Match object at 0x1006d10b8>