WebSocket握手期间出错：PHP的“ Sec-WebSocket-Accept”标头值不正确

Question

我已经用PHP编写了websocket服务器/客户端代码，并且在两年内为我工作。现在它不起作用，说：Error during WebSocket handshake: Incorrect 'Sec-WebSocket-Accept' header value

我的客户端代码本质上是这样的：

socket = new WebSocket("ws://<?= EVENT_SERVER_ADDR ?>:"+EVENT_SERVER_PORT+"<?= EVENT_SERVER_WWW_PATH ?>");

PHP服务器端代码是这样的：

list ($resource, $host, $connection, $version, $origin, $key, $protocol, $upgrade) = $this->getheaders ($buffer);

$this->log ("Handshaking...");
$reply  = 
    "HTTP/1.1 101 Switching Protocols\r\n" .
    "Upgrade: {$upgrade}\r\n" .
    "Connection: {$connection}\r\n" .
    "Sec-WebSocket-Version: {$version}\r\n" .
    "Sec-WebSocket-Origin: {$origin}\r\n" .
    "Sec-WebSocket-Location: ws://{$host}{$resource}\r\n" .
    "Sec-WebSocket-Accept: " . $this->calcKey ($key) . "\r\n";
if ($protocol)
    $reply .= "Sec-WebSocket-Protocol: $protocol\r\n";
$reply .=   "\r\n";

// Closes the handshake
socket_write ($user->socket, $reply, strlen ($reply));

function calcKey ($key) {
    // Constant string as specified in the ietf-hybi-17 draft
    $key .= "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
    $key = sha1 ($key, true);
    // $key = pack ('H*', $key); // should I uncomment this line?
    $key = base64_encode ($key);

    return $key;
}

function getheaders ($buffer) {
    $resource = $host = $connection = $version = $origin = $key = $protocol = $upgrade = null;

    preg_match ('#GET (.*?) HTTP#', $buffer, $match) && $resource = $match[1];
    preg_match ("#Host: (.*?)\r\n#", $buffer, $match) && $host = $match[1];
    preg_match ("#Connection: (.*?)\r\n#", $buffer, $match) && $connection = $match[1];
    preg_match ("#Sec-WebSocket-Version: (.*?)\r\n#", $buffer, $match) && $version = $match[1];
    preg_match ("#Origin: (.*?)\r\n#", $buffer, $match) && $origin = $match[1];
    preg_match ("#Sec-WebSocket-Key:\s*(.*?)\r\n#", $buffer, $match) && $key = $match[1];
    preg_match ("#Sec-WebSocket-Protocol:\s*(.*?)\r\n#", $buffer, $match) && $protocol = $match[1];
    preg_match ("#Upgrade: (.*?)\r\n#", $buffer, $match) && $upgrade = $match[1];

    return array ($resource, $host, $connection, $version, $origin, $key, $protocol, $upgrade);
}

有趣的是，这些人只是在不保持旧代码正常运行且没有在线说任何内容的情况下更改了标准（我真的非常努力地用谷歌搜索）。有人知道我有什么问题吗？

Answer 1

所以我找出了问题所在。这就是缓冲区限制。

显然，该变量$buffer仅包含约4 KB的数据，并且由于来自dataTables的cookie，因此输入数据要多得多。而Sec-WebSocket-Key头部是所有Cookie之后。所以$key每次都是空的，给错了Sec-WebSocket-Accept。

建议：进行更深入的调试。