我有以下课程
public class ModInfo : IEquatable<ModInfo>
{
public int ID { get; set; }
public string MD5 { get; set; }
public bool Equals(ModInfo other)
{
return other.MD5.Equals(MD5);
}
public override int GetHashCode()
{
return MD5.GetHashCode();
}
}
Run Code Online (Sandbox Code Playgroud)
我使用如下方法将一些数据加载到该类的列表中:
public void ReloadEverything() {
var beforeSort = new List<ModInfo>();
// Bunch of loading from local sqlite database.
// not included since it's reload boring to look at
var modinfo = beforeSort.OrderBy(m => m.ID).AsEnumerable().Distinct().ToList();
}
Run Code Online (Sandbox Code Playgroud)
问题是Distinct()呼叫似乎没有做到这一点.仍然存在彼此相等的对象.
根据这篇文章:https://msdn.microsoft.com/en-us/library/vstudio/bb348436%28v=vs.100%29.aspx这 是你应该如何做出不同的工作,但它不似乎是在ModInfo对象上调用Equals方法.是什么导致这种情况发生?
示例值:
modinfo[0]: id=2069, MD5 =0AAEBF5D2937BDF78CB65807C0DC047C
modinfo[1]: id=2208, MD5 = 0AAEBF5D2937BDF78CB65807C0DC047C
Run Code Online (Sandbox Code Playgroud)
我不关心选择哪个值,因为md5值相同,它们可能是相同的.
您还需要覆盖Object.Equals,而不仅仅是实现IEquatable.
如果你把它添加到你的班级:
public override bool Equals(object other)
{
ModInfo mod = other as ModInfo;
if (mod != null)
return Equals(mod);
return false;
}
Run Code Online (Sandbox Code Playgroud)
它应该工作.
有关更多信息,请参阅此文章:正确实现IEquatable
编辑:好的,这是基于GetHashCode的最佳实践的略有不同的实现.
public class ModInfo : IEquatable<ModInfo>
{
public int ID { get; set; }
public string MD5 { get; set; }
public bool Equals(ModInfo other)
{
if (other == null) return false;
return (this.MD5.Equals(other.MD5));
}
public override int GetHashCode()
{
unchecked
{
int hash = 13;
hash = (hash * 7) + MD5.GetHashCode();
return hash;
}
}
public override bool Equals(object obj)
{
ModInfo other = obj as ModInfo;
if (other != null)
{
return Equals(other);
}
else
{
return false;
}
}
}
Run Code Online (Sandbox Code Playgroud)
你可以验证它:
ModInfo mod1 = new ModInfo {ID = 1, MD5 = "0AAEBF5D2937BDF78CB65807C0DC047C"};
ModInfo mod2 = new ModInfo {ID = 2, MD5 = "0AAEBF5D2937BDF78CB65807C0DC047C"};
// You should get true here
bool areEqual = mod1.Equals(mod2);
List<ModInfo> mods = new List<ModInfo> {mod1, mod2};
// You should get 1 result here
mods = mods.Distinct().ToList();
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4001 次 |
| 最近记录: |