如何根据两个值过滤arraylist

Question

我有一个项目列表,其中每个项目都包含产品价格,现在我想根据用户输入过滤我的arraylist

我接受最低和最高价格范围,现在我想显示仅在这些价格范围内的记录.

我正在使用btnSearch过滤列表,以显示两个值之间的记录,就像我想要显示那些在这两个值内的记录;

20000至50000

btnSearch.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                editMin.getText().toString();
                editMax.getText().toString();
            }
        });

我使用下面的代码来过滤基于高价到低价范围的记录,为此我使用下面的代码:

btnHTL.setOnClickListener(new OnClickListener() {

@Override
public void onClick(View arg0) {
// TODO Auto-generated method stub

Collections.sort(arrayList, new Comparator<Home>() {

    @Override
    public int compare(Home arg1, Home arg2) {
    // TODO Auto-generated method stub
        Integer obj1 = new Integer(arg1.getPrice().replace(",", ""));
        Integer obj2 = new Integer(arg2.getPrice().replace(",", ""));
        return (obj2).compareTo(obj1);
     }
   });

   for (int i = 0; i < arrayList.size(); i++) {
      System.out.println("HTL:--" + arrayList.get(i).getPrice());                    
    }
      adapter.notifyDataSetChanged();
    }
  });

Answer 1

    btnSearch.setOnClickListener(new OnClickListener() { 

@Override 
public void onClick(View v) { 
// TODO Auto-generated method stub 

Integer objMin = new Integer(editMin.getText().toString()); 
Log.d("min:", String.valueOf(objMin)); 
Integer objMax = new Integer(editMax.getText().toString()); 
Log.d("max:", String.valueOf(objMax)); 

ArrayList<Home> temp_arraylist = new ArrayList<Home>(); 

for (int i = 0; i < arrayList.size(); i++) { 

int price = (Integer.parseInt(arrayList.get(i).getPrice().replace(",", ""))); 

if(price >= objMin && price <= objMax){ 
temp_arraylist.add(arrayList.get(i)); 
} 

} 

adapter = new HomeAdapter(getApplicationContext(), R.layout.adapter_home, temp_arraylist); 
listview.setAdapter(adapter); 

} 
});

并比较对象的arraylist ..请参阅此链接http://beginnersbook.com/2013/12/java-arraylist-of-object-sort-example-comparable-and-comparator/