kam*_*aci 1 java processbuilder
我使用 Process Builder 运行 shell 命令:
try {
ProcessBuilder lmBuilder = new ProcessBuilder("/home/istanbul/srilm/bin/i686-m64/ngram-count", "-text", modelPath, "-order", "3", "-lm", modelOutputPath);
lmBuilder.redirectErrorStream();
final Process lmProcess = lmBuilder.start();
int result = lmProcess.waitFor(); //result becomes 0
InputStream is = lmProcess.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;
while ((line = br.readLine()) != null) {
System.out.println(line);
}
} catch (IOException | InterruptedException e) {
e.printStackTrace();
}
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当我检查命令的输出时,我发现它工作正常。当我通过 shell 运行它时,我看到输出:
warning: discount coeff 1 is out of range: 0
warning: discount coeff 7 is out of range: 1.06876
warning: discount coeff 7 is out of range: 2.09945
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但是,当我通过进程生成器运行它时,我看不到任何输出。
有任何想法吗?
lmBuilder.redirectErrorStream();
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这是不正确的。
此方法仅告诉您是否将 stderr 重定向到 stdout;它不指示 stderr 应重定向到它。
你应该使用的是:
lmBuilder.redirectErrorStream(true);
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