在R中生成多个字符的(随机)序列

Question

1. 我可以使用创建一系列单个字母

   LETTERS[seq( from = 1, to = 10 )]
   letters[seq( from = 1, to = 10 )]
   

2. 我可以使用random包创建一个不同长度的随机字符串

   library(random)
   string <- randomStrings(n=10, len=5, digits=TRUE, upperalpha=TRUE,
                     loweralpha=TRUE, unique=TRUE, check=TRUE)
   

不幸的是,我不能使用该set.seed功能2.

有没有办法在每次运行R文件时创建(唯一)字符串的相同(随机)组合？

我的结果看起来像这样(每次运行函数时都会得到相同的结果):

       V1     
  [1,] "k7QET"
  [2,] "CLlWm"
  [3,] "yPuwh"
  [4,] "JJqEX"
  [5,] "38soF"
  [6,] "xkozk"
  [7,] "uaiOW"
  [8,] "tZcrW"
  [9,] "8K4Cc"
 [10,] "RAhuU"

Answer 1

在文件中,例如test.R,添加以下内容

set.seed(1)
stringi::stri_rand_strings(10, 5)

然后它每次都可以重现.

replicate(5, source("test.R", verbose = FALSE)$value)
#       [,1]    [,2]    [,3]    [,4]    [,5]    
#  [1,] "GNZuC" "GNZuC" "GNZuC" "GNZuC" "GNZuC" 
#  [2,] "twed3" "twed3" "twed3" "twed3" "twed3"
#  [3,] "CAgNl" "CAgNl" "CAgNl" "CAgNl" "CAgNl"
#  [4,] "UizNm" "UizNm" "UizNm" "UizNm" "UizNm" 
#  [5,] "vDe7G" "vDe7G" "vDe7G" "vDe7G" "vDe7G"
#  [6,] "N0NrL" "N0NrL" "N0NrL" "N0NrL" "N0NrL"
#  [7,] "TbUBp" "TbUBp" "TbUBp" "TbUBp" "TbUBp"
#  [8,] "fn6iP" "fn6iP" "fn6iP" "fn6iP" "fn6iP" 
#  [9,] "oemYW" "oemYW" "oemYW" "oemYW" "oemYW"
# [10,] "m1Tjg" "m1Tjg" "m1Tjg" "m1Tjg" "m1Tjg"

作为替代方案source(),您可以parse()在那里使用.

replicate(5, eval(parse("test.R")))

Answer 2

基础R的替代解决方案:

set.seed(1)
result <- rawToChar(as.raw(sample(c(65:90,97:122), 5, replace=T)))

灵感来自另一篇文章的回答:https://stackoverflow.com/a/4370074/8297546