Symfony中的Monolog来自非控制器类

Question

我有以下课程:

namespace AppBundle\EventListener;

use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use FOS\UserBundle\Event\UserEvent;
use FOS\UserBundle\FOSUserEvents;
use FOS\UserBundle\Event\FormEvent;


class UserRegistrationListener implements EventSubscriberInterface
{

     protected $logger;
     public function __construct($logger)
     {
           $this->logger = $logger;
     }

    public static function getSubscribedEvents()
    {
        return array(
            FOSUserEvents::REGISTRATION_INITIALIZE => 'onRegistrationInit',
        );
    }

    /**
     * take action when registration is initialized
     * set the username to a unique id
     * @param \FOS\UserBundle\Event\FormEvent $event
     */
    public function onRegistrationInit(UserEvent $userevent)
    {
        $this->logger->info("Log Something");

        $user = $userevent->getUser();

        $user->setUsername(uniqid());
    }
}

而且我一直在努力用几个小时的时间记录一下monolog的东西,但没有运气.

我已经阅读了很多文档,我相信我需要以某种方式'注入'monolog作为服务.然而,我所读到的内容似乎并不清楚.

一些细节:

#config_dev.yml
monolog:
    channels: [chris]
    handlers:
        mylog:
            type:   stream
            path:   "%kernel.logs_dir%/%kernel.environment%_chris.log"
            channels: chris
            formatter: monolog.my_line_formatter

.

#services.yml   
 services:
        monolog.my_line_formatter: 
            class: Monolog\Formatter\LineFormatter
            arguments: [~, ~, true]

        app.user_registration:
            class: AppBundle\EventListener\UserRegistrationListener
            arguments: [@logger] ## changed to [@monolog.logger.chris] to us custom channel
            tags:
                - { name: kernel.event_subscriber }

我需要做些什么才能让Monolog在我的课程中使用我的格式化程序？

更新: @griotteau我已经完成了你在答案中发布的内容,但我仍然收到错误消息:

CRITICAL - 未捕获的PHP异常Symfony\Component\Debug\Exception\ContextErrorException:"警告:缺少参数1的AppBundle\EventListener\UserRegistrationListener :: __ construct(),在... filepath ...\app\cache\dev\appDevDebugProjectContainer中调用.php在第384行并定义为"at ... filepath ...\src\AppBundle\EventListener\UserRegistrationListener.php第18行

已解决的错误我已经有了同一个班级的服务(未在ym问题中显示).@griotteau的回答是正确的.

Answer 1

您可以在声明服务时传递参数

在services.yml中:

 app.user_registration:
    class: AppBundle\EventListener\UserRegistrationListener
    arguments: [@logger]
    tags:
        - { name: kernel.event_subscriber }  

在您的类中,添加一个构造函数:

protected $logger;
public function __construct($logger)
{
        $this->logger = $logger;        
}

所以当你想添加一个日志时:

$this->logger->info(...);