如何通过在输入中输入内容来显示程序的结果？

Question

所以,我有一个程序,我正在完成,但我显然遇到了问题.在程序中,我必须在输入中输入0时,程序将停止并打印结果.在我继续说出其他任何内容之前,这是程序:

import collections
students = collections.defaultdict(list)

while True:
    student = input("Enter a name: ").replace(" ","")
    if student == "0":
        print ("A zero has been entered(0)")
        break

    if not student.isalpha():
            print ("You've entered an invalid name. Try again.")
            continue

    while True:
        grade = input("Enter a grade: ").replace(" ","")
        if grade == "0":
            print ("A zero has been entered(0)")
            break

        if not grade.isdigit():
            print ("You've entered an invalid name. Try again.")
            continue

        grade = int(grade)
        if 1 <= grade <= 10:
            students[student].append(grade)
            break

for i, j in students.items():
    print ("NAME: ", i)
    print ("LIST OF GRADES: ", j)
    print ("AVERAGE: ", round(sum(j)/len(j),1))

我找到了一种方法,如何在程序中输入0后停止并发布结果"Enter a name: ".这是打印出来的:

Enter a name: Stacy
Enter a grade: 8
Enter a name: 0
A zero has been entered(0)
NAME:  Stacy
LIST OF GRADES:  [8]
AVERAGE:  8.0

我需要对部件做同样的事情,"Enter a grade: "但如果我尝试使程序像现在一样,这就是打印出来的:

Enter a name: Stacy
Enter a grade: 0
A zero has been entered(0)
Enter a name: 

如何在程序输入中输入0时,程序显示结果？

Answer 1

在您的输入之一中，检查输入是否为 0。如果是，请调用sys.exit。这可以在任何地方完成，甚至在检查成绩时也是如此。只需确保包含两个选项（字符串 0 和整数 0）。另外，它仍然这样说的原因A zero has been entered(0)是因为你只是退出一个循环，然后基本上从头开始。

# Be sure to import sys!

random_place = input("Whatever is here ")
if random_place == '0' or random_pace == 0:
    sys.exit(0)

然后你的程序就会退出。