如何使用模式匹配查找重复的字符串？

Question

我有一个与此类似的字符串:

[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> |Hunit:Player-3693-07420299:DevnullYour [Chimaera Shot] hit |Hunit:Creature-0-3693-1116-3-87318-0000881AC4:Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature. 

如果你想知道,它来自魔兽世界.

我想结束这样的事情:

[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training Dummy 33265 Nature. 

如果你注意到,"Dungeoneer's Training Dummy"会被打印两次.我设法用这样的东西摆脱了第一个"| Hunit"部分:

str = "[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> |Hunit:Player-3693-07420299:DevnullYour [Chimaera Shot] hit |Hunit:Creature-0-3693-1116-3-87318-0000881AC4:Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature."
str = string.gsub(str, "|Hunit:.*:.*Your", "Your")

哪个返回:

print(str)    # => [13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit |Hunit:Creature-0-3693-1116-3-87318-0000881AC4:Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature.

然后我添加第二个gsub:

str = string.gsub(str, "|Hunit:.*:", "")
print(str) # => [13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature.

但显然,重复了双重"Dungeoneer's Training Dummy"字符串.

我怎么能摆脱重复的字符串？这个字符串可以是其他任何东西,在这种情况下是"Dungeoneer's Training Dummy",但它可以是任何其他目标的名称.

Answer 1

你可以尝试这样的事情:

str = "[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature."
-- find a string that starts with 'hit', has some number of non-digits
-- and ends with one or more digit and one or more characters.
-- these characters will be "captured" into three strings,
-- which are then passed to the "replacement" function.
-- the returned result of the function replaces the value in the string.
str = str:gsub("(hit%s+)([^%d]+)(%d+.+)", function(s1, s2, s3)
    local s = s2:gsub("%s+$","") -- drop trailing spaces
    if #s % 2 == 0 -- has an even number of characters
    and s:sub(0, #s / 2) -- first half
    == -- is the same
    s:sub(#s / 2 + 1) -- as the second half
    then -- return the second half
      return s1..s:sub(#s / 2 + 1)..' '..s3
    else
      return s1..s2..s3
    end
  end)
print(str)

这打印: [13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training Dummy

此代码将尝试提取目标的名称并检查名称是否为完整副本.如果匹配失败,则返回原始字符串.