使用gre中的grep和子集的多个过滤器

Question

我正在尝试创建一个过滤器,以使用grep和subset一起从数据集中删除线条.

样本数据集:

id <- 1:10
problem <- c("a" , "b", "c", "d", "a","b","c","a", "b", "a")
solution1 <- c("eat", "sleep", "drink", "play", "sleep", "play", "play", "drink", "play", "eat")
solution2 <- c("read", "read", "eat", "drink", "eat", "sleep", "eat", "read", "eat", "play")
df <- c(id, problem, solution1, solution2)

我试图删除问题"a"的那些行,并在solution1或solution2中"吃".

结果是它应该删除id 1,5和10.

我尝试过使用:

df <- subset(df, problem=="a" & !(grepl("eat", df)))

和

df <- df[!grepl("eat", df) & grepl("a", df$problem)]

似乎无法在StackOverflow或我用Google搜索的其他网站上找到类似的解决方案.

如果有人能提供帮助,我将不胜 谢谢!

Answer 1

首先,如果你想要一个数据帧,你应该使用data.frame,而不是c:

df <- data.frame(id, problem, solution1, solution2)

然后你可以像这样的子集(不需要使用子集本身)

df2 <- df[!(grepl("a", df$problem) & 
           (grepl("eat", df$solution1) |
            grepl("eat", solution2))),]

#   id problem solution1 solution2
# 2  2       b     sleep      read
# 3  3       c     drink       eat
# 4  4       d      play     drink
# 6  6       b      play     sleep
# 7  7       c      play       eat
# 8  8       a     drink      read
# 9  9       b      play       eat