Django 1.5为pk> 999提供404s

Question

我正在尝试做的事情 我有一个简单的视图,它将pk作为参数并执行操作.这个工作正常,直到pks大于999.现在他们返回404s.我正在努力解决这个问题.

我尝试过的内容 我的观点如下:

def request_publication(request, pk):
    ...
    article = News.all_news.get(pk=pk) # all_news is a manager including unpublished articles
    article.status = article.HIDDEN_STATUS
    article.save()
    ...

网址正则表达式是这样的:

regex=r'^request-publication/(?P<pk>\d+)/',

我也尝试过:

regex=r'^request-publication/(?P<pk>\d{4})/',

这使得它在pks <1000时失败,但仍不适用于pk> 999.

完整的urls.py是:

# core Django imports
from django.conf.urls import patterns, include, url

# local imports
from .models import News, Category, Attachment
from .views import (
    NewsHomeView,
    CategoryHomeView,
    NewsDetailView,
    NewsYearArchiveView,
    NewsMonthArchiveView,
    NewsDayArchiveView,
    NewsListView,
    NewsCreateView,
    NewsUpdateView,
    publish,
    request_publication,
)

urlpatterns = patterns('',
    url(
        regex = r'^$',
        view = NewsHomeView.as_view(),
        name = "news_home",
        ),
    url(
        regex = r'^add/$',
        view = NewsCreateView.as_view(),
        name = 'news_add',
    ),
    url(
        regex = r'^update/(?P<pk>\d+)/$',
        view = NewsUpdateView.as_view(),
        name = 'news_update',
    ),
    url(
        regex = r'^(?P<slug>[-\w]+)/$',
        view = CategoryHomeView.as_view(),
        name = 'category_detail',
        ),
    url(
        regex = r'^tag/(?P<tag_slug>[-\w]+)/$',
        view = NewsListView.as_view(),
        name = 'news_tag_list',
    ),
    url(
        regex = r'^(?P<category>[-\w]+)/(?P<year>\d{4})/$',
        view = NewsYearArchiveView.as_view(),
        name = "year_archive",
        ),
    url(
        regex = r'^(?P<category>[-\w]+)/(?P<year>\d{4})/(?P<month>\w{3})/$',
        view = NewsMonthArchiveView.as_view(),
        name = "month_archive",
        ),
    url(
        regex = r'^(?P<category>[-\w]+)/(?P<year>\d{4})/(?P<month>\w{3})/(?P<day>\d{2})/$',
        view = NewsDayArchiveView.as_view(),
        name = "day_archive",
        ),
    url(
        regex = r'^(?P<category>[-\w]+)/(?P<year>\d{4})/(?P<month>\w{3})/(?P<day>\d{2})/(?P<slug>[-\w]+)/$',
        view = NewsDetailView.as_view(),
        name = "article",
        ),
    url(
        regex = r'^publish/(?P<pk>\d+)/$',
        view = publish,
        name = 'publish',
    ),
    url(
        regex = r'^request-publication/(?P<pk>\d+)/$',
        view = request_publication,
        name = 'request_publication',
    ),
)

News.all_news.get(pk=1000)从shell 调用是完美的,all_news作为标准Django objects管理器的别名,因为我已经覆盖objects了自定义管理器.

我所期待的, 我看不出有什么理由会失败.我期待视图成功返回.

实际发生的事情 标准404页面.

限制 由于公司限制,我无法单独升级到更新的Django.

问题 有没有其他人经历过这个,你是如何解决的？

Answer 1

请求request-publication/1000被year-archive视图捕获,因为它与r'^(?P<category>[-\w]+)/(?P<year>\d{4})/$三位数pk不匹配时的模式匹配.

因此,您获得404,因为您在1000年中没有发布与"请求 - 发布"子弹匹配的项目.