拆分列表并在python中存储在字典中

Question

假设我有一个列表,如

L = ['B0','B1','C1','C2','D1','D3']

然后,我如何将列表拆分为值和键,并以下列形式将其存储在字典中: -

{ 'B':['0','1'],
  'C':['1','2'],
  'D':['1','3']}

Answer 1

L = ['B0','B1','C1','C2','D1','D3']
d = {}
for i in L:
    d.setdefault(i[0], []).append(i[1])

>>> d
{'B': ['0', '1'], 'C': ['1', '2'], 'D': ['1', '3']}

Answer 2

您可以遍历列表并中断每个字符串元素以创建字典.试试这个:

from collections import defaultdict

l = ['B0','B1','C1','C2','D1','D3']
d = defaultdict(list)

for key, value in l:
    d[key].append(value)

print d