我已经开始学习Haskell了,而且我一直在读"为了大好学习你是一个Haskell".我读完了模块章节的一半.一位朋友向我展示了代码战,我决定将我学到的一些内容用于测试.
我正在尝试创建一个函数,该函数返回给定Integral是否为4的幂的布尔值.这是代码.
module PowerOfFour where
isWhole n = fromIntegral (round n) == n
isPowerOf4 :: Integral n => n -> Bool
isPowerOf4 4 = True
isPowerOf4 x = if x < 4 then
False
else
if isWhole (x / 4) then
isPowerOf4 (truncate (x / 4))
else
False
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这是我收到的错误消息.
/tmp/haskell11524-8-kke52v/PowerOfFour.hs:10:12:
Could not deduce (RealFrac n) arising from a use of `isWhole'
from the context (Integral n)
bound by the type signature for
isPowerOf4 :: Integral n => n -> Bool
at /tmp/haskell11524-8-kke52v/PowerOfFour.hs:5:15-37
Possible fix:
add (RealFrac n) to the context of
the type signature for isPowerOf4 :: Integral n => n -> Bool
In the expression: isWhole (x / 4)
In the expression:
if isWhole (x / 4) then isPowerOf4 (truncate (x / 4)) else False
In the expression:
if x < 4 then
False
else
if isWhole (x / 4) then isPowerOf4 (truncate (x / 4)) else False
/tmp/haskell11524-8-kke52v/PowerOfFour.hs:10:23:
Could not deduce (Fractional n) arising from a use of `/'
from the context (Integral n)
bound by the type signature for
isPowerOf4 :: Integral n => n -> Bool
at /tmp/haskell11524-8-kke52v/PowerOfFour.hs:5:15-37
Possible fix:
add (Fractional n) to the context of
the type signature for isPowerOf4 :: Integral n => n -> Bool
In the first argument of `isWhole', namely `(x / 4)'
In the expression: isWhole (x / 4)
In the expression:
if isWhole (x / 4) then isPowerOf4 (truncate (x / 4)) else False
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我究竟做错了什么?
我在isWhole中使用fromIntegral来修复类似的错误,并且isWhole现在可以单独使用.但是,我似乎无法摆脱isPowerOf4中的这些错误.我已经尝试过GHC提供的可能修复程序,但我可能没有做到这一点.
我宁愿保留isPowerOf4函数的类型签名,因为这是由代码新闻提供的,所以我猜它是一个要求.
在Haskell中,/运算符是分数类型而不是整数类型.对于你应该使用的整数类型div(你可以通过在反引号中包围它来使用它的中缀).您也可以使用mod或rem查找剩余部分,例如%典型语言(负数不同)
isPowerOf4 :: Integral n => n -> Bool
isPowerOf4 4 = True
isPowerOf4 x = if x < 4
then False
else
if x `mod` 4 == 0
then isPowerOf4 (x `div` 4)
else False
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