Python Denary到二进制转换器

IOS*_*mer 0 python binary

嗨,你能帮我把denary值转换成二进制和十六进制吗?我必须输入0到15之间的数字,输出应该是十六进制和二进制等价.这是我到目前为止所做的:

    denary_list=           ["0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15"]
    print("denary list")


binary_list=["0000","0001","0010","0011","0100","0101","0110","0111","1000","1001","1010","1011","1100","1101","1110","1111"]
print("binary list")

hex_list=["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"]
print("hex list")
option=input("enter choice:\n1.print values\n2.convert denary number to binary and hex\n3. Convert a hex value between 0 and 15 to denary or binary value\n9. Quit")
if option=='1':
   print ("denary","\t","binary","hex")
   count1=0
   while count1<len(denarylist) and count1<len(binarylist) and count1<len(hexlist):
       print(denarylist[count1],"\t",binarylist[count1],"\t",hexlist[count1])
       count1+=1
if option=='2':
  number=int(input("what number do you choose to convert to binary and hex"))
  if number<=15 and number>=0:
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Ant*_*ala 5

使用该format方法代替bx格式化代码将整数格式化为十六进制或二进制数:

>>> format(1234, 'b')
'10011010010'
>>> format(1234, 'x')
'4d2'
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使用int('01234fff', 16)一个十六进制字符串转换为数字; 同样int('11110000', 2)地将二进制字符串转换为数字.


并回答你原来的问题:你可以得到第一项(从零开始索引),binary_list[number]所以你可以把你的选项2写成

number = int(input("what number do you choose to convert to binary and hex"))
if 0 <= number <= 15:
    print("the number in binary is", binary_list[number])
    print("the number in hex is", hex_list[number])
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