如何构建'坏'值的数组

JM4*_*JM4 1 php arrays

我正在处理表格,然后根据提交的信息收到回复代码.我手中有一个大约40个响应代码(及其含义)的列表,我正在尝试构建一个检查预定义数组并返回特定值的'if'语句.

只是不知道该怎么做

概念上第一次通过:

$bads = array (1,2,3,4,5,6)


if ($output['responsecode'] == (any value in $bads) {
echo "you suck";
}
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编辑 - 仍然收到错误

我使用以下代码:

$bad_resp1 = array("D","M","A","B","W","Z","P","L","N","C","U","G","I","R","E","S","0","O","B");
$bad_resp2 = array("N","P","S","U");
$bad_resp3 = array("200","201","202","203","204","220","221","222","223","224","225","250","261","262","263","264","300","400","410","411","420","421","430","440","441","460","461"); 
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然后调用'if'语句:

if (in_array($output['response1'], $bad_resp1) || in_array($output['response2'], $bad_resp2) || in_array($output['response3'], $bad_resp3)) {
            Header("Location: fail.php");
        }
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我收到以下错误:

警告:in_array()期望参数2为数组,在第362行的C:\ xampp\htdocs\site\xyz.php中给出null

警告:in_array()期望参数2为数组,在第362行的C:\ xampp\htdocs\site\xyz.php中给出null

警告:in_array()期望参数2为数组,在第362行的C:\ xampp\htdocs\site\xyz.php中给出null

Amy*_*y B 9

使用 in_array()

if (in_array($output['responsecode'], $bads)) { echo "you suck"; }
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Tim*_*per 7

in_array

if(in_array($output['responsecode'], $bads))
{

}
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此外,如果您的代码是顺序的,您可以使用范围来生成数组.

$bad = range(1, 10);
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