骰子滚动直方图
Ete*_*por 1 java histogram dice
我有一个类问题,我似乎无法理解其逻辑.
修改下面的程序以打印直方图,其中通过打印像*那样的字符来显示骰子滚动等于每个可能值的总次数,如下所示.
直方图显示每个可能值的骰子总数.
骰子滚动直方图:
2: ******
3: ****
4: ***
5: ********
6: *******************
7: *************
8: *************
9: **************
10: ***********
11: *****
12: ****
我不明白这个直方图显示的是什么.它让我疯了,如果我不明白我在做什么,我无法继续我的逻辑.我知道之前已经问过这个问题,但看起来他们都有特定数量的骰子角色.我没有得到一个数字,这就是让我失望的原因.我知道这真是一个愚蠢的问题.但任何人都可以向我解释他们的意思是"直方图显示每个可能值的骰子总数"这是什么定义了这个可能值？我完全失去了...任何帮助表示赞赏.这是我到目前为止编写的代码.
import java.util.Scanner;
import java.util.Random;
public class DiceStats {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
Random randGen = new Random();
int i = 0; // Loop counter iterates numRolls times
int numRolls = 0; // User defined number of rolls
int numOnes = 0; // Tracks number of 1's found
int numTwos = 0; // Tracks number of 2's found
int numThrees = 0; // Tracks number of 3's found
int numFours = 0; // Tracks number of 4's found
int numFives = 0; // Tracks number of 5's found
int numSixes = 0; // Tracks number of 6's found
int numSevens = 0; // Tracks number of 7's found
int numEights = 0; // Tracks number of 8's found
int numNines = 0; // Tracks number of 9's found
int numTens = 0; // Tracks number of 10's found
int numElevens = 0; // Tracks number of 11's found
int numTwelves = 0; // Tracks number of 12's found
int die1 = 0; // Dice values
int die2 = 0; // Dice values
int rollTotal = 0; // Sum of dice values
System.out.println("Enter number of rolls: ");
numRolls = scnr.nextInt();
if (numRolls >= 1) {
// Roll dice numRoll times
for (i = 0; i < numRolls; ++i) {
die1 = randGen.nextInt(6) + 1;
die2 = randGen.nextInt(6) + 1;
rollTotal = die1 + die2;
// Count number of sixes and sevens
if (rollTotal == 1) {
numOnes = numOnes + 1;
}
if (rollTotal == 2) {
numTwos = numTwos + 1;
}
if (rollTotal == 3) {
numThrees = numThrees + 1;
}
if (rollTotal == 4) {
numFours = numFours + 1;
}
if (rollTotal == 5) {
numFives = numFives + 1;
}
if (rollTotal == 6) {
numSixes = numSixes + 1;
}
if (rollTotal == 7) {
numSevens = numSevens + 1;
}
if (rollTotal == 8) {
numEights = numEights + 1;
}
if (rollTotal == 9) {
numNines = numNines + 1;
}
if (rollTotal == 10) {
numTens = numTens + 1;
}
if (rollTotal == 11) {
numElevens = numElevens + 1;
}
else if (rollTotal == 12) {
numTwelves = numTwelves + 1;
}
System.out.println("Roll " + (i+1) + " is " + rollTotal + " (" + die1 +
"+" + die2 + ")");
}
// Prints a histogram of the number of dice rolls
System.out.println("\nDice roll histogram:");
System.out.println("1's: " + numOnes);
System.out.println("2's: " + numTwos);
System.out.println("3's: " + numThrees);
System.out.println("4's: " + numFours);
System.out.println("5's: " + numFives);
System.out.println("6's: " + numSixes);
System.out.println("7's: " + numSevens);
System.out.println("8's: " + numEights);
System.out.println("9's: " + numNines);
System.out.println("10's: " + numTens);
System.out.println("11's: " + numElevens);
System.out.println("12's: " + numTwelves);
}
else {
System.out.println("Invalid rolls. Try again.");
}
return;
}
}
您可以看到我输入直方图条目的位置.我基本上认为我需要编辑从"numOnes"这样的整数给出的值到星号,但现在我不确定......任何帮助都表示赞赏!
编辑代码 -
System.out.println("\nDice roll histogram:");
System.out.print("2's: ");
for(i = 0; i < numTwos; i++){
System.out.print("*");
}
System.out.println("");
System.out.print("3's: ");
for (i = 0; i < numThrees; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("4's: " );
for (i = 0; i < numFours; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("5's: ");
for (i = 0; i < numFives; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("6's: ");
for (i = 0; i < numSixes; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("7's: ");
for (i = 0; i < numSevens; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("8's: ");
for (i = 0; i < numEights; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("9's: ");
for (i = 0; i < numNines; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("10's: ");
for (i = 0; i < numTens; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("11's: ");
for (i = 0; i < numElevens; i++);{
System.out.print("*");
}
System.out.println("");
System.out.print("12's: ");
for (i = 0; i < numTwelves; i++);{
System.out.print("*");
}
System.out.println("");
}
产量 -
Enter number of rolls:
5
Roll 1 is 8 (2+6)
Roll 2 is 9 (6+3)
Roll 3 is 9 (5+4)
Roll 4 is 6 (4+2)
Roll 5 is 9 (6+3)
Dice roll histogram:
2's:
3's: *
4's: *
5's: *
6's: *
7's: *
8's: *
9's: *
10's: *
11's: *
12's: *
我可以输入更多的卷,我会得到2的星号,它会像我需要的那样增加,但它不会增加其余的数字,它们都只能得到一个星号.是什么让我的代码不能正确增加*的数量？我已经和它斗争了好几个小时:/
"我不明白这个直方图显示的是什么."
好吧,正如你所说:
"直方图显示每个可能值的骰子总数"
直方图:
2: ******
3: ****
4: ***
5: ********
6: *******************
7: *************
8: *************
9: **************
10: ***********
11: *****
12: ****
是一对六面骰子的记录.总共一对骰子的可能值范围从2到12.如果你将它们滚动100次,它们可能会给出这些结果.
该直方图显示值6最常滚动(19次),4次最不频繁滚动(3次).如果你计算每一个*,你就知道掷骰子的次数.
您可能认为直方图必须如下所示:
但转向侧面:
并且想象蓝色条是*,100 - 150标签是a 2,150 - 200标签是a 3,然后它开始看起来像你的直方图.
两种形式都是直方图.它们可以让您比较属于不同类别(种类)的事物的数量(多少).
图形图表很难从基于文本的程序中输出,因此它要求您显示基本的ascii艺术:
如果这是在文本文件中,而不是程序输出,这也可以被认为是一种形式.您可以在收到新数据时轻松添加新*.这是同样的伎俩:
希望更有意义.
SPOILER ALERT:如果这有帮助并且您想要修改程序,那么请不要再阅读.除此以外...
这个
System.out.println("\nDice roll histogram:");
System.out.println(" 1's: " + nManyStars(numOnes));
System.out.println(" 2's: " + nManyStars(numTwos));
System.out.println(" 3's: " + nManyStars(numThrees));
System.out.println(" 4's: " + nManyStars(numFours));
System.out.println(" 5's: " + nManyStars(numFives));
System.out.println(" 6's: " + nManyStars(numSixes));
System.out.println(" 7's: " + nManyStars(numSevens));
System.out.println(" 8's: " + nManyStars(numEights));
System.out.println(" 9's: " + nManyStars(numNines));
System.out.println("10's: " + nManyStars(numTens));
System.out.println("11's: " + nManyStars(numElevens));
System.out.println("12's: " + nManyStars(numTwelves));
还有这个
static String nManyStarsOld(int n) {
String result = "";
for (int i = 0; i < n; i++) {
result += "*";
}
return result;
}
应该,如果放在正确的位置,让程序停止打印现在打印的内容,这是:
Enter number of rolls:
20
Roll 1 is 5 (2+3)
Roll 2 is 10 (4+6)
Roll 3 is 7 (5+2)
Roll 4 is 7 (5+2)
Roll 5 is 5 (1+4)
Roll 6 is 11 (6+5)
Roll 7 is 8 (3+5)
Roll 8 is 8 (2+6)
Roll 9 is 7 (1+6)
Roll 10 is 8 (3+5)
Roll 11 is 12 (6+6)
Roll 12 is 6 (2+4)
Roll 13 is 8 (6+2)
Roll 14 is 8 (4+4)
Roll 15 is 7 (1+6)
Roll 16 is 4 (2+2)
Roll 17 is 6 (5+1)
Roll 18 is 7 (6+1)
Roll 19 is 6 (1+5)
Roll 20 is 5 (1+4)
Dice roll histogram:
1's: 0
2's: 0
3's: 0
4's: 1
5's: 3
6's: 3
7's: 5
8's: 5
9's: 0
10's: 1
11's: 1
12's: 1
相反,让它打印出来:
Dice roll histogram:
1's:
2's:
3's:
4's: *
5's: ***
6's: ***
7's: *****
8's: *****
9's:
10's: *
11's: *
12's: *
下次发布问题时,请包括当前输出和预期输出.
如果你觉得自己是一个聪明的裤子,实际上有一个版本的nManyStars():
static String nManyStars(int n) {
return new String(new char[n]).replace("\0", "*");
}
灵感来自:https://stackoverflow.com/a/4903603/1493294
此外,如果您有至少11 Java的可以交易的nManyStars(n)对"*".repeat(n)
希望能帮助到你
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