访问JSON数据属性

Question

我有以下字符串

{
    data: [
                {"Href":"1.jpg","Id":1,"Height":55,"Width":55,"Index":0},
                {"Href":"2.jpg","Id":2,"Height":55,"Width":55,"Index":1},
                {"Href":"3.jpg","Id":3,"Height":55,"Width":55,"Index":2},
                {"Href":"4.jpg","Id":4,"Height":55,"Width":55,"Index":3}
            ]
}

转换回json

 var data = Newtonsoft.Json.JsonConvert.DeserializeObject<dynamic>(parsedString);

我的问题是:

我怎样才能访问每个JSON属性,例如Something.Href提取1.jpg,2.jpg或仅Id属性？

Answer 1

我建议使用"LINQ to JSON"而不是DeserializeObject个人 - 尽管这可能只是因为它有更多的经验:

using System;
using System.IO;

using Newtonsoft.Json.Linq;

class Program
{
    static void Main(string[] args)
    {
        string text = File.ReadAllText("Test.json");

        var json = JObject.Parse(text);
        var data = json["data"];
        foreach (var item in data)
        {
            Console.WriteLine(item["Href"]);
        }
    }
}

话虽如此,你可以DeserializeObject很好地使用,只需动态访问成员:

using System;
using System.IO;

using Newtonsoft.Json;

class Program
{
    static void Main(string[] args)
    {
        string text = File.ReadAllText("Test.json");
        var json = JsonConvert.DeserializeObject<dynamic>(text);
        var data = json.data;
        foreach (var item in data)
        {
            Console.WriteLine(item.Href);
        }
    }
}