选择 java 备份并尝试熟悉枚举类型。我正在尝试创建一个地址簿,用户可以在其中创建联系人。我已经创建了所有内容,但是我在设置联系人类型(家庭、朋友、业务等...)时遇到了麻烦,我已经在单独的 Java 类中设置了一个枚举类。
public class ContactType
{
public enum contactType
{
Family,
Church,
Friend,
BusninessColleague,
ServicePerson,
Customer,
Other
}
}
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我的 Contacts 类看起来像:
public class Contacts
{
private contactType contact;
private String name;
private String streetAddress;
private String city;
private String state;
private String zipCode;
private String phone;
private String email;
private String photo;
public Contacts ( )
{
contact = null;
name = "XXX XXX";
streetAddress = "XXX";
state = "XX";
zipCode = "00000";
phone = "XXX-XXXX";
email = "XXX@XXX.COM";
photo = "XXX.jpg";
}
public Contacts (ContactType contactType, String name, String streetAddress, String city,
String state, String zipCode, String phone, String email, String photo)
{
this.contact = contactType;
this.name = name;
this.streetAddress = streetAddress;
this.city = city;
this.state = state;
this.zipCode = zipCode;
this.phone = phone;
this.email = email;
this.photo = photo;
}
public ContactType getContactType ( )
{
return contact;
}
public void setContactType (ContactType input)
{
this.contact = input;
}
//rest of code
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最后是我的驱动程序,它包含一个菜单(除了设置联系人类型之外,其他所有内容都可以使用,因此我只是包含了该代码段以保持简短):
public class ContactType
{
public enum contactType
{
Family,
Church,
Friend,
BusninessColleague,
ServicePerson,
Customer,
Other
}
}
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我知道我在这里做错了,c1.setContactType(strContactType);因为我得到“Contacts 类型中的方法 setContactType(ContactType) 不适用于参数 (String)”,这是由于完全无知我不知道如何修复它以设置用户输入的任何内容的 contactType。
您的问题是您调用valueOf(...)但丢弃了此方法调用返回的 ContactType 对象......即,您从未将返回的对象分配给变量。
首先通过更改以下内容来摆脱不必要的包装:
public class ContactType
{
public enum contactType
{
Family,
Church,
Friend,
BusninessColleague,
ServicePerson,
Customer,
Other
}
}
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对此:
public enum ContactType
{
Family,
Church,
Friend,
BusninessColleague,
ServicePerson,
Customer,
Other
}
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接下来使用 valueOf 设置 ContactType 变量。
strContactType = JOptionPane.showInputDialog ("Please enter contact type (Family, Church, BusinessColleague, ServicePerson, Customer, or Other)");
ContactType contactType = ContactType.valueOf(strContactType);
JOptionPane.showMessageDialog (null, strContactType);
c1.setContactType (contactType);
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请注意,我会尝试通过将选择限制为 ContactType 来使其更加防白痴。例如:
Object selection = JOptionPane.showInputDialog(null,
"Choose a contact type", "Contact Type",
JOptionPane.INFORMATION_MESSAGE, null,
ContactType.values(), ContactType.values()[0]);
// check that selection is not null before using
System.out.println(selection);
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