if(array[3][3].getCall() == false && array[3][3].getUser() == Car.user.NONE )
{
array[3][3] = new Car('s', Car.user.USER, false);
aCounter++;
System.out.println("everything is fine");
}
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这段代码告诉我:错误:无法从静态上下文引用非静态变量用户.
public class Car
{
public enum User { USER, COMP, NA };
private char object;
public User user;
private boolean call;
public Car(char object, User user, boolean call)
{
this.object = object;
this.user = user;
this.call = call;
}
}
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枚举是公开的,因为我得到"用户有私人访问错误".我知道枚举是一个在构造函数中声明的非静态变量,所以我认为这是错误的来源,但我不知道如何解决它.
该问题与枚举变量无关,与静态字段和类与非静态字段和类有关.请注意,当你写
Car.user.NONE
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Car.user指的是在类上命名的字段 - 但它是一个实例变量,而不是静态变量.因此,错误:userCarCar.user
non-static variable user cannot be referenced from a static context
要解决此问题,只需更改Car.user为Car.User以便表达式引用enum User而不是User user字段.
if(array[3][3].getCall() == false && array[3][3].getUser() == Car.User.NONE )
{
array[3][3] = new Car('s', Car.User.USER, false);
aCounter++;
System.out.println("everything is fine");
}
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