我有一个看起来像这样的字符串向量,我想将它拆分:
str <- c("Fruit LoopsJalapeno Sandwich", "Red Bagel", "Basil LeafBarbeque SauceFried Beef")
str_split(str, '[a-z][A-Z]', n = 3)
[[1]]
[1] "Fruit Loop" "alapeno Sandwich"
[[2]]
[1] "Red Bagel"
[[3]]
[1] "Basil Lea" "arbeque Sauc" "ried Beef"
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但我需要将这些字母保留在最后和单词的开头.
这是基础中的两种方法(如果需要,可以概括为stringr).
这个用一个占位符将这个地方分开,然后拆分.
strsplit(gsub("([a-z])([A-Z])", "\\1SPLITHERE\\2", str), "SPLITHERE")
## [[1]]
## [1] "Fruit Loops" "Jalapeno Sandwich"
##
## [[2]]
## [1] "Red Bagel"
##
## [[3]]
## [1] "Basil Leaf" "Barbeque Sauce" "Fried Beef"
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此方法使用前瞻和后观:
strsplit(str, "(?<=[a-z])(?=[A-Z])", perl=TRUE)
## [[1]]
## [1] "Fruit Loops" "Jalapeno Sandwich"
##
## [[2]]
## [1] "Red Bagel"
##
## [[3]]
## [1] "Basil Leaf" "Barbeque Sauce" "Fried Beef"
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编辑广泛使用stringr, 这样你就可以获得3件作品
stringr::str_split(gsub("([a-z])([A-Z])", "\\1SPLITHERE\\2", str), "SPLITHERE", 3)
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