如何使用可选参数创建构造函数？

Question

我有__construct($参数)

public function __construct($nick) {
    $query = "SELECT * FROM Users WHERE nick='".$nick."'";
    $result = App::runQuery($query);
    $user = $result->fetch_object();

    $this->id = $user->id;
    $this->nick = $user->nick;
    $this->email = $user->email;
    $this->password = $user->password;
    $this->birthDay = $user->birthDay;
    $this->sex = $user->sex;
    $this->about = $user->about;
    $this->city = $user->city;
    $this->photo = $user->photo;
    $this->following = $user->following;
    $this->followers = $user->followers;
    $this->statu = $user->statu; 

}

现在我想要一个没有这样参数的默认构造函数:

public function __construct() {

    $this->id = NULL;
    $this->nick = NULL;
    $this->email = NULL;
    $this->password = NULL;
    $this->birthDay = NULL;
    $this->sex = NULL;
    $this->about = NULL;
    $this->city = NULL;
    $this->photo = NULL;
    $this->following = NULL;
    $this->followers = NULL;
    $this->statu = NULL; 

}

但有些事情是错误的,我得到这样的错误:

Fatal error: Cannot redeclare User::__construct() in /Applications/MAMP/htdocs/xxx/Application/User.php on line 33

如何让两个带参数且没有参数的构造函数同时出现？

Answer 1

1. PHP中没有重载; 你不能拥有相同名称但参数不同的方法

2. 由于您的所有属性都将默认为null,因此没有理由自己执行此操作.我建议做以下事情:

   public function __construct($nick = null) {
       if ($nick != null) {
           $query = "SELECT * FROM Users WHERE nick='".$nick."'";
           $result = App::runQuery($query);
           $user = $result->fetch_object();
   
           $this->id = $user->id;
           $this->nick = $user->nick;
           $this->email = $user->email;
           $this->password = $user->password;
           $this->birthDay = $user->birthDay;
           $this->sex = $user->sex;
           $this->about = $user->about;
           $this->city = $user->city;
           $this->photo = $user->photo;
           $this->following = $user->following;
           $this->followers = $user->followers;
           $this->statu = $user->statu; 
       }
   }
   

3. 上面代码的替代方法是使用多个静态构造函数方法,并使用私有构造函数:

   private function __construct() {
   }
   
   public static function createFromNick($nick) {
       $self = new self();
   
       $query = "SELECT * FROM Users WHERE nick='".$nick."'";
       $result = App::runQuery($query);
       $user = $result->fetch_object();
   
       $self->id = $user->id;
       $self->nick = $user->nick;
       $self->email = $user->email;
       $self->password = $user->password;
       $self->birthDay = $user->birthDay;
       $self->sex = $user->sex;
       $self->about = $user->about;
       $self->city = $user->city;
       $self->photo = $user->photo;
       $self->following = $user->following;
       $self->followers = $user->followers;
       $self->statu = $user->statu;
   
       return $self;
   }
   
   public static function createEmpty() {
       return new self();
   }
   

Answer 2

非常感谢您的回答。我已经用我的方法解决了这个问题。

public function __construct($nick) {
    if($nick != NULL) {//for user 
        $query = "SELECT * FROM Users WHERE nick='".$nick."'";
        $result = App::runQuery($query);
        $user = $result->fetch_object();

        $this->id = $user->id;
        $this->nick = $user->nick;
        $this->email = $user->email;
        $this->password = $user->password;
        $this->birthDay = $user->birthDay;
        $this->sex = $user->sex;
        $this->about = $user->about;
        $this->city = $user->city;
        $this->photo = $user->photo;
        $this->following = $user->following;
        $this->followers = $user->followers;
        $this->statu = $user->statu; 
    }else {//for null
        $this->id = NULL;
        $this->nick = NULL;
        $this->email = NULL;
        $this->password = NULL;
        $this->birthDay = NULL;
        $this->sex = NULL;
        $this->about = NULL;
        $this->city = NULL;
        $this->photo = NULL;
        $this->following = NULL;
        $this->followers = NULL;
        $this->statu = NULL;
    }

}

有用！