Phi*_*yck 13 c# async-await entity-framework-6
我正在尝试下面的代码,它有两个部分,一个是通过棱镜导航.当允许导航时,我以异步方式开始深度加载,但每次都使用新的上下文.在以后的代码中,我想要取消未完成此加载的挂起导航,但下面的代码甚至不起作用,因此取消是稍后的事情;-)
导航逻辑:这里没问题
public void OnNavigatedTo(NavigationContext navigationContext)
{
int relatieId = (int)navigationContext.Parameters["RelatieId"];
if (_relatie != null && _relatie.RelatieId == relatieId) return;
loadRelatieAsync(relatieId);
}
public void ConfirmNavigationRequest(NavigationContext navigationContext, Action<bool> continuationCallback)
{
bool navigationAllowed = true;
continuationCallback(navigationAllowed);
}
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深度加载逻辑:
private async Task loadRelatieAsync(int relatieId)
{
try
{
await Task.Run(async () =>
{
_unitOfWork = _UnitOfWorkFactory.createUnitOfWorkAsync();
IEnumerable<Relatie> relaties = await getRelatieAsync(_unitOfWork, relatieId).ConfigureAwait(true);
_relatieTypeTypes = await getRelatieTypeTypesAsync(_unitOfWork, relatieId).ConfigureAwait(true);
_relatie = relaties.FirstOrDefault();
_unitOfWork.Dispose();
}).ConfigureAwait(true);
processRelatie(_relatie);
processRelatieTypes(_relatie, _relatieTypeTypes);
}
catch (Exception Ex)
{
MessageBox.Show(Ex.Message);
throw;
}
}
private async Task<IEnumerable<Relatie>> getRelatieAsync(IUnitOfWorkAsync unitOfWork, int relatieId)
{
IEnumerable<Relatie> relaties = null;
try
{
IRepositoryAsync<Relatie> relatieRepository = unitOfWork.RepositoryAsync<Relatie>();
relaties = await relatieRepository
.Query(r => r.RelatieId == relatieId)
.Include(i => i.BegrafenisOndernemer)
.SelectAsync()
.ConfigureAwait(false);
IRepositoryAsync<Adres> adresRepository = unitOfWork.RepositoryAsync<Adres>();
//exception is thrown after executing following line
var adressen = await adresRepository
.Query(r => r.RelatieId == relatieId)
.Include(i => i.AdresType)
.SelectAsync()
.ConfigureAwait(false);
_relatieTypeRepository = unitOfWork.RepositoryAsync<RelatieType>();
var relatieTypes = await _relatieTypeRepository
.Query(r => r.RelatieId == relatieId)
.SelectAsync()
.ConfigureAwait(false);
}
catch (Exception Ex)
{
MessageBox.Show(Ex.Message);//exception is shown here
throw;
}
return relaties;
}
private async Task<IEnumerable<RelatieTypeType>> getRelatieTypeTypesAsync(IUnitOfWorkAsync unitOfWork, int relatieId)
{
IEnumerable<RelatieTypeType> relatieTypeTypes = null;
try
{
IRepositoryAsync<RelatieTypeType> relatieTypeTypeRepository =
unitOfWork.RepositoryAsync<RelatieTypeType>();
relatieTypeTypes = await relatieTypeTypeRepository
.Query()
.SelectAsync()
.ConfigureAwait(false);
}
catch (Exception Ex)
{
MessageBox.Show(Ex.Message);
throw;
}
return relatieTypeTypes;
}
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我一直得到例外,好像我忘了等待,但事实并非如此.每当我想在GUI线程上继续时,我也正确使用configureawait(true).但我一直在深度加载逻辑中得到这个错误.工作单元和存储库类也使用异步等待机制,但我正在等待正确.
在先前的异步操作完成之前,在该上下文上开始第二操作.使用'await'确保在此上下文上调用另一个方法之前已完成任何异步操作.任何实例成员都不保证是线程安全的.
编辑(删除记录器代码以减少代码大小)
Phi*_*yck 16
问题是这段代码:
_unitOfWork = _UnitOfWorkFactory.createUnitOfWorkAsync();
IEnumerable<Relatie> relaties = await getRelatieAsync(_unitOfWork, relatieId).ConfigureAwait(true);
_relatieTypeTypes = await getRelatieTypeTypesAsync(_unitOfWork, relatieId).ConfigureAwait(true);
_relatie = relaties.FirstOrDefault();
_unitOfWork.Dispose();
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UnitOfWork是一个实例变量,当场景第二次被新实例覆盖时.然后,已经执行的场景使用新的UnitOfWork而不是它自己的,因为它被覆盖了.不是那么容易发现,而是简单的竞争条件.我通过用局部变量替换所有实例变量来找到它,然后问题就消失了.