tem*_*sun 4 c# asp.net gridview
我正在尝试在gridview c#asp.net中的rowdatabound中创建按钮并单击事件,如下代码
protected void btnerror_Click(object sender, EventArgs e)
{
GridView gv = new GridView();
gv.RowDataBound += gv_RowDataBound;
gv.RowCommand += gv_RowCommand;
gv.RowCreated += gv_RowCreated;
gv.EnableViewState = true;
gv.DataSource = _dt;
gv.DataBind();
}
void gv_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
ImageButton btnUpdate = new ImageButton();
btnUpdate.ID = "btnupdate";
btnUpdate.ImageUrl = "~/SmartAdmin/Images/update.png";
btnUpdate.ToolTip = "Click Update";
btnUpdate.CommandName = "update";
btnUpdate.Click += btnUpdate_Click;
TableCell tc = new TableCell();
tc.Controls.Add(btnUpdate);
e.Row.Cells.Add(tc);
}
}
void gv_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName == "update")
{
}
}
Run Code Online (Sandbox Code Playgroud)
当单击该按钮单击事件未触发时...
我在哪里出错了...
感谢你.......
您真的要GridView手动创建吗?我对此表示强烈怀疑。而是以声明方式将其添加到aspx-page并在中使其可见btnerror_Click。
不要动态创建控件并RowDataBound在RowCreated其中注册事件处理程序,但在每次回发中都会触发该事件处理程序(与相对RowDataBound):
void gv_RowCreated(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
ImageButton btnUpdate = new ImageButton();
btnUpdate.Click += btnUpdate_Click;
TableCell tc = new TableCell();
tc.Controls.Add(btnUpdate);
e.Row.Cells.Add(tc);
}
}
void gv_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
ImageButton btnUpdate = (ImageButton)e.Row.FindControls("btnupdate")
btnUpdate.ID = "btnupdate";
btnUpdate.ImageUrl = "~/SmartAdmin/Images/update.png";
btnUpdate.ToolTip = "Click Update";
btnUpdate.CommandName = "update";
}
}
Run Code Online (Sandbox Code Playgroud)
因此RowCreated,请在RowDataBound其中创建它,但在您可以访问数据源的地方对其进行初始化(如果需要)。
另外请注意,你应该DataBind在GridView只if(!IsPostBack)不是每次回发(如果是这样的话)。因此,请在分配数据源的位置添加此检查。