选择小于特定分钟的以分钟为单位的日期时间差

Question

我有一个这样的查询：

SELECT DATEDIFF(minute,t.Paydate,t.DelDate) as Mtime 
       FROM Transaction_tbl t WHERE Locid=6 

这将返回如下结果：

Mtime
8
2
10
20
15
7
6

但是，在该查询中，我必须给出条件，例如我只想显示小于 10 分钟或小于 15 分钟的结果。我还有一张桌子，它是location。在那，我有一个数据类型Time(0)的列timeinterval。实际上这个值我想在同一个查询中传递。那么我如何在不到 10 分钟的时间内重写我的查询显示结果呢？

Answer 1

AND在WHERE子句中添加条件：

SELECT  
    DATEDIFF(MINUTE, t.Paydate, t.DelDate) AS Mtime 
FROM Transaction_tbl t 
WHERE 
    Locid = 6
    AND DATEDIFF(MINUTE,t.Paydate,t.DelDate) < 10

根据您的新疑问：

SELECT  
    DATEDIFF(MINUTE, t.Paydate, t.DelDate) AS Mtime,
    COUNT(*) AS Count 
FROM Transaction_tbl t 
WHERE 
    Locid = 6
GROUP BY Mtime
HAVING DATEDIFF(MINUTE, t.Paydate, t.DelDate) < 10

你可以做这样的事情

SELECT  
   case when ( DATEDIFF(MINUTE, t.Paydate, t.DelDate)<10) then DATEDIFF(MINUTE, t.Paydate, t.DelDate) else null end AS lessthan10,
case when ( DATEDIFF(MINUTE, t.Paydate, t.DelDate)>10) then DATEDIFF(MINUTE, t.Paydate, t.DelDate) else null end AS greaterthan10,
    COUNT(*) AS Count 
FROM Transaction_tbl t 
WHERE 
    Locid = 6
GROUP BY Mtime
HAVING DATEDIFF(MINUTE, t.Paydate, t.DelDate) < 10