在go lang,为什么这是7？断言(5 ^ 2 == 7)

Question

在go lang,为什么这是7？

assert(5^2 == 7)

这么奇怪.我试着去谷歌吧.但谷歌与特殊字符不兼容.谢谢.

Answer 1

该^操作符是XOR(异或),逐位施加如果操作数是数字.

5 = 101b // in binary, but Go doesn't have binary literals
2 = 010b
XOR:
7 = 111b

Answer 2

It is an Arithmetic operators:

^    bitwise XOR            integers

You can see it on this Bitwise Calculator

Result in binary    111