Mal*_*nge 4 java dictionary treemap
我有以下两个类来定义我想要放入TreeMap的对象:
class GeneKey {
String PN;
int PW;
// Generator makes unique TreeMap key.
GeneKey(String a, int b){
this.PN = a;
this.PW = b;
}
}
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然后是第二个对象:
class GeneValue {
String info;
String date;
// Generator makes TreeMap value
GeneValue(String a, String b){
this.info = a;
this.date = b;
}
}
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我想制作一个TreeMap:
import java.util.TreeMap;
// In main ...
TreeMap<GeneKey, GeneValue> samples = new TreeMap<GeneKey, GeneValue>();
String a = "test";
int b = 100;
String c = "test again";
String d = "test yet again";
// Try to put these objects into the tree map.
samples.put(new GeneKey(a, b) ,new GeneValue(c,d))
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但是我收到以下错误:
Exception in thread "main" java.lang.ClassCastException: GeneKey cannot be cast to java.lang.Comparable
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我想知道为什么我无法使用key:GeneKey:GeneValue的值建立TreeMap,即使我在初始化TreeMap时指定了这些对象.如何初始化地图以便.put()这两个对象.
谢谢
TreeMap 是一个有序的容器:当您请求其密钥或其条目时,您可以按特定顺序获取它们.
订单取决于您提供的密钥.为了使容器能够对密钥进行排序,每个密钥都需要实现Comparable接口:
class GeneKey implements Comparable<GeneKey> {
String PN;
int PW;
// Generator makes unique TreeMap key.
GeneKey(String a, int b){
this.PN = a;
this.PW = b;
}
public int compareTo(GenKey other) {
int res = PN.compareTo(other.PN);
return (res != 0) ? res : Integer.compare(PW, other.PW);
}
}
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这不是基于散列的容器的要求,因为所有东西都来自Object,提供hashCode和equals.
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