读取zip存档中的文件,而不解压缩存档

Question

我有一个包含100多个zip文件的目录,我需要读取zip文件中的文件来进行一些数据处理,而不需要解压缩存档.

是否有一个Ruby库来读取zip存档中的文件内容,而不解压缩文件？

使用rubyzip会出错:

require 'zip'

Zip::File.open('my_zip.zip') do |zip_file|
  # Handle entries one by one
  zip_file.each do |entry|
    # Extract to file/directory/symlink
    puts "Extracting #{entry.name}"
    entry.extract('here')

    # Read into memory
    content = entry.get_input_stream.read
  end
end 

给出了这个错误:

test.rb:12:in `block (2 levels) in <main>': undefined method `read' for Zip::NullInputStream:Module (NoMethodError)
    from .gem/ruby/gems/rubyzip-1.1.6/lib/zip/entry_set.rb:42:in `call'
    from .gem/ruby/gems/rubyzip-1.1.6/lib/zip/entry_set.rb:42:in `block in each'
    from .gem/ruby/gems/rubyzip-1.1.6/lib/zip/entry_set.rb:41:in `each'
    from .gem/ruby/gems/rubyzip-1.1.6/lib/zip/entry_set.rb:41:in `each'
    from .gem/ruby/gems/rubyzip-1.1.6/lib/zip/central_directory.rb:182:in `each'
    from test.rb:6:in `block in <main>'
    from .gem/ruby/gems/rubyzip-1.1.6/lib/zip/file.rb:99:in `open'
    from test.rb:4:in `<main>'

Answer 1

该Zip::NullInputStream条目是否为一个目录,而不是一个文件被退回,可能是这样的话？

这是一个更强大的代码变体:

#!/usr/bin/env ruby

require 'rubygems'
require 'zip'


Zip::File.open('my_zip.zip') do |zip_file|
  # Handle entries one by one
  zip_file.each do |entry|
    if entry.directory?
      puts "#{entry.name} is a folder!"
    elsif entry.symlink?
      puts "#{entry.name} is a symlink!"
    elsif entry.file?
      puts "#{entry.name} is a regular file!"

      # Read into memory
      content = entry.get_input_stream.read

      # Output
      puts content
    else
      puts "#{entry.name} is something unknown, oops!"
    end
  end
end