Sam*_* Su 0 mysql sql inner-join left-join where
表:书签
bid bname tagid1 tagid2 tagid3
--------------------------------------------------------------------
1 bookmark1 1001 1002 1003
2 bookmark2 1002 1005
3 bookmark3 1003 1003
4 bookmark4 1003
5 bookmark5 1001
6 bookmark5 1002 1003
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表:标签
tagid tagname
--------------------------
1001 Java
1002 PHP
1003 Ruby
1004 Node.js
1005 Go
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我期望获得的结果是:
bid bname tagName1 tagName2 tagName3
--------------------------------------------------------------------
1 bookmark1 Java PHP Ruby
2 bookmark2 PHP Go
3 bookmark3 Ruby Ruby
4 bookmark4 Ruby
5 bookmark5 Java
6 bookmark5 PHP Ruby
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我怎么能得到这个?
您需要多次加入同一个表.您需要每个表名别名来区分它们
select b.id, b.bname,
t1.name as tagName1,
t2.name as tagName2,
t3.name as tagName3
from bookmark b
left join tag t1 on t1.tagid = b.tagid1
left join tag t2 on t2.tagid = b.tagid2
left join tag t3 on t3.tagid = b.tagid3
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顺便说一句,你应该考虑通过添加另一个用于书签标签映射的表来改变你的表设计.然后,您可以为每个书签添加任意数量的标签.