当我使用 spring-data-jpa 时,“java.lang.IllegalArgumentException:该位置 [1] 的参数不存在”

use*_*083 5 java hibernate spring-data-jpa

我正在使用spring-data-jpa + hibernate。1.我遇到以下异常......

Caused by: java.lang.IllegalArgumentException: Parameter with that position [1] did not exist
    at org.hibernate.jpa.spi.BaseQueryImpl.findParameterRegistration(BaseQueryImpl.java:518) ~[BaseQueryImpl.class:4.3.7.Final]
    at org.hibernate.jpa.spi.BaseQueryImpl.setParameter(BaseQueryImpl.java:674) ~[BaseQueryImpl.class:4.3.7.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:198) ~[AbstractQueryImpl.class:4.3.7.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:49) ~[AbstractQueryImpl.class:4.3.7.Final]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:165) ~[ParameterBinder.class:?]
    at org.springframework.data.jpa.repository.query.StringQueryParameterBinder.bind(StringQueryParameterBinder.java:66) ~[StringQueryParameterBinder.class:?]
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......

  1. 我相信例外来自

    public interface FamousExperienceDao extends PagingAndSortingRepository<FamousExperience,
      Long>,JpaSpecificationExecutor<FamousExperience>
    {
        @Query( value = 
            "select new com.tujia.community.entity.BriefInfomation(f.id,f.title,f.summary,f.thumbnail,f.author, f.issueDate, f.counter) from FamousExperience f"
            ,countQuery ="select count(f.id) from FamousExperience f")
        public Page<BriefInfomation> findExps(Specification<FamousExperience> spec, Pageable pgbl);
    }
    
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因为在我从函数 findExps 的参数中删除规范规范后,它工作得很好,我只想为查询添加规范。

BYW,FamousExperience 类扩展了 BriefInfomation。我使用了 JPA 查询的“构造函数表达式”功能,当我尝试查询时,我只是不需要属性“内容”。

@Entity
@Table(name = "famous_experience")
public class FamousExperience extends BriefInfomation
    {
    private String content;

    /**
     * @return the content
     */
    public String getContent()
    {
        return content;
    }

    /**
     * @param content the content to set
     */
    public void setContent(String content)
    {
        this.content = content;
    }
}
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请帮助我!

Chr*_*era 0

如果您在那里有规范规范,则需要在查询中的某个地方引用它...重要的是,当您在那里有可分页时,计数器似乎不会从 ?0 开始,而是从 ?1 开始

所以这样的事情应该有效

 @Query( value = 
    "from FamousExperience f where f.spec = ?1"
    ,countQuery ="select count(f.id) from FamousExperience f")
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