具有所有子列表变体的单列表的Pythonic方式

Question

我确信这个简单的问题有答案,但我真的不知道如何用英语表达(惭愧),所以决定问人类.

假设我有一个列表列表:

[['Sometimes'], [' '], ['I'], [' '], ['love', 'hate'], [' '], ['pizza', 'coke']]

什么是获得以下输出的最pythonic方式？

['Sometimes I love pizza', 'Sometimes I love coke', 'Sometimes I hate pizza', 'Sometimes I hate coke']

Answer 1

from itertools import product

options = [['Sometimes'],[' '],['I'],[' '],['love','hate'],[' '],['pizza','coke']]

for combo in product(*options):
    print("".join(combo))

给

Sometimes I love pizza
Sometimes I love coke
Sometimes I hate pizza
Sometimes I hate coke