Swift枚举作为函数中的参数

Question

我有一个存储枚举的类,并提供一个函数,如果枚举作为参数给出,则将此枚举显示为字符串.

enum ErrorType: String {
    case InvalidInputTextFieldEmpty = "One or more inputs seem empty. Please enter your credentials."
    case InvalidInputPasswordsNotMatch = "Please check your passwords they doesn't seem to match."
}

class ErrorManager: NSObject {
    func handleError(errorType: ErrorType)
    {
        self.showAlertView(errorType.rawValue)
    }

    func showAlertView(message:String)
    {
        var alertView:UIAlertView = UIAlertView(title: "Notice", message: message, delegate: self, cancelButtonTitle: "OK")
        alertView.show()
    }
}

现在我想在另一个类中访问函数handleError: ErrorManager.handleError(ErrorType.InvalidInputTextFieldEmpty)

但编译抱怨参数是n0t,如果有类型ErrorManager虽然我写的参数是类型ErrorType.我在这做错了什么？

Answer 1

当您将方法声明为实例方法时,您尝试将该方法作为类方法进行访问.您需要创建ErrorManager类的实例并将其用作方法调用中的接收器,或者将方法声明更改为类方法,如下所示:

class ErrorManager: NSObject {
    class func handleError(errorType: ErrorType) {
        ErrorManager.showAlertView(errorType.rawValue)
    }

    class func showAlertView(message: String) {
        let alertView = UIAlertView(title: "Notice", message: message, delegate: self, cancelButtonTitle: "OK")
        alertView.show()
    }
}