递归CTE - 查找经理以下的所有员工

Question

我为这个SQLFIDDLE创建了一个示例小提琴

CREATE TABLE [dbo].[Users](
    [userId] [int] ,
    [userName] [varchar](50) ,
    [managerId] [int] ,
   )

INSERT INTO dbo.Users
    ([userId], [userName], [managerId])
VALUES
(1,'Darry',NULL),
(2,'Cono',1),
(3,'Abros',2),
(4,'Natesh',1),
(5,'Ani',3),
(6,'Raju',5),
(7,'Pinky',5),
(8,'Miya',4)

我的要求就是在特定经理下方显示所有员工层级

这是我试过的

WITH UserCTE AS (
  SELECT userId, userName, managerId, 0 AS EmpLevel
  FROM Users where managerId IS NULL

  UNION ALL

  SELECT usr.userId, usr.userName, usr.managerId, mgr.[EmpLevel]+1
  FROM Users AS usr
    INNER JOIN UserCTE AS mgr
      ON usr.managerId = mgr.userId where usr.managerId IS NOT NULL
)
SELECT * 
  FROM UserCTE AS u where u.ManagerId=3
  ORDER BY EmpLevel;

输出:

userName
--------
    Ani

我期待的输出是,如果我给ManagerId 3,那么应该显示以下员工

1.Abros
2.Ani
3.Raju
4.Pinky

任何人都可以帮助这个

Answer 1

试试这个.必须在Anchor queryCTE中应用过滤器

WITH UserCTE
     AS (SELECT userId,
                userName,
                managerId,
                0 AS EmpLevel
         FROM   [Users]
         WHERE  managerId = 3
         UNION ALL
         SELECT usr.userId,
                usr.userName,
                usr.managerId,
                mgr.[EmpLevel] + 1
         FROM   [Users] AS usr
                INNER JOIN UserCTE AS mgr
                        ON usr.managerId = mgr.userId
         WHERE  usr.managerId IS NOT NULL)
SELECT *
FROM   UserCTE AS u
ORDER  BY EmpLevel; 

FIDDLE DEMO