"foo =(foo + 1)%bar"到底是做什么的？

Question

来自Finch音频库:

- (void) play
{
    [[sounds objectAtIndex:current] play];
    current = (current + 1) % [sounds count]; // this line here...
}

我试着理解它:有许多声音n,并且current每次迭代都会增加1.一旦current大于声音数n,则模数返回零.这样,它从头开始.

它是否正确？

Answer 1

恩,那就对了.