如何在php混合数字,低位和高位字母中生成增量ID?
例如,我尝试过:
$hello = "aaa0";
for ($i=0; $i < 10000; $i++) {
echo $hello++;
echo "<br>";
}
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然后,它返回;
aaa0
aaa1
aaa2
...
aaa9
aab0
aab1
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我想生成字符串:
aaa0
aaa1
aaa2
...
aaaa
aaab
aaac
...
aaaz
aaaA
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第一个数字从0到9,然后是从a到z的字符,然后是从A到Z的字符.每个位置字符都应该在此范围内.
我该怎么做?
编辑:我希望字符串中的每个字符都在此范围内变化.我想从0到9,然后是a到z,然后是A到Z.当它结束时,char变为0,左边的char增加为1.例如:
0000
0001
0002
...
0009
000a
000b
...
000y
000z
000A
000B
...
000X
000Z
0010
0011
0012
....
0019
001a
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这应该适合你:
<?php
$hello = "aaa";
//'aaa0' -> 'aaa9'
for ($count = 0; $count <= 9; $count++)
echo $hello . $count . "<br />";
//'aaaa' -> 'aaaz'
foreach (range('a', 'z') as $char)
echo $hello . $char . "<br />";
//'aaaA' -> 'aaaZ'
foreach (range('A', 'Z') as $char)
echo $hello . $char . "<br />";
?>
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编辑:
这仅适用于3位数.内存耗尽后肯定是.
<?php
$array = array();
$maxLength = 3;
$output = array();
ini_set('memory_limit', '-1');
$time_start = microtime(true);
foreach(range(0, 9) as $number)
$array[] = $number;
foreach(range('a', 'z') as $char)
$array[] = $char;
foreach(range('A', 'Z') as $char)
$array[] = $char;
function everyCombination($array, $arrLength, $size, $perArr = array(), $pos = 0, &$found = array()) {
if ($size == $pos) {
$found[] = vsprintf("%s%s%s", $perArr);
return;
}
for ($count = 0; $count < $arrLength; $count++) {
$perArr[$pos] = $array[$count];
everyCombination($array, $arrLength, $size, $perArr, $pos+1, $found);
}
return $found;
}
$output = everyCombination($array, count($array), $maxLength);
for($count = 0; $count < count($output); $count++)
echo $output[$count] . "<br/>";
echo "DONE!";
$time_end = microtime(true);
$time = $time_end - $time_start;
echo round($time,2) . " s";
?>
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使用 0,1-9、az 和 AZ 是“Base 62”。在 PHP 中从 10 进制转换为 62 进制非常容易。
<?php
echo base_convert(10123, 10,26), "\n";
// outputs: 'ep9'
echo base_convert('ep9', 26, 10), "\n";
// output 10123
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