ZipArchive无法打开文件 - 错误代码:19

Question

我的代码能够打开我已经上传并移动到文件夹的zip文件的问题,zip文件上传很好,你可以在任何Zip程序中打开它然而,当我尝试用ZipArchive打开它来提取数据错误.

    $path = "../"; // Upload directory      
    $count = 0;

    foreach ($_FILES['files']['name'] as $f => $name) {     
       if(move_uploaded_file($_FILES["files"]["tmp_name"][$f], $path . $name))
             $count++; // Number of successfully uploaded file
    }

    $kioskFile = $_FILES['files']['name'][0];
    $kioskFile = explode(".", $kioskFile);
    $kioskFile = $kioskFile[0];
    $zipFile = "../" . $kioskFile . ".zip";     

    $zip = new ZipArchive;
    $res = $zip->open($zipFile);
    if ($res === true) {
        $zip->extractTo("./");
        $zip->close();
    } else {
        echo "Error Cannot Open Zip File - Error Code: ";
    }

当我运行代码时,它向我显示错误代码19

ZIPARCHIVE :: ER_NOZIP - 19

这是我得到的错误,但文件存在,如果我使用zip_open,它返回它可以打开zip文件.

任何帮助都会非常棒

EDIT1 如果我上传我手动创建的zip文件(使用zip程序),那么上传工作正常.但是,如果我使用ZipArchive创建的zip文件,那么它会立即出错并出现错误19.

EDIT2 我现在添加了一个检查,以确保该文件存在于正确的目录中,并且还放置了该位置的打印,两者都匹配,但仍然是相同的问题.错误19

    $path = "../"; // Upload directory      
    $count = 0;

    foreach ($_FILES['files']['name'] as $f => $name) {     
       if(move_uploaded_file($_FILES["files"]["tmp_name"][$f], $path . $name))
             $count++; // Number of successfully uploaded file
    }

    $kioskFile = $_FILES['files']['name'][0];
    $kioskFile = explode(".", $kioskFile);
    $kioskFile = $kioskFile[0];
    $realpath = realpath("../");
    $zipFile = $realpath . "\\" .  $kioskFile . ".zip";     

    if (file_exists($zipFile)) {
        $extract = zip_extract($zipFile, "../");
        if ($extract === TRUE) {

        } else {
            echo "The file " . $zipFile . " cannot be opened";  
        }
    } else {
        echo "The file " . $zipFile . " does not exist";
        die();
    }

UPDATE1 所以我想我已经把它缩小到这个代码,或者我用来从系统下载.zip文件的下载脚本,如果我把zip保留在系统上并使用它完全相同的代码精细.

这是我的下载代码,也许我错过了导致问题的一些事情.

    $fileID = $_GET['id'];
    $backupLoc = "backups/";
    $sql = "SELECT * FROM backups WHERE id = '" . addslashes($fileID) .  "' LIMIT 1";
    $res = mysql_query($sql);
    $row = mysql_fetch_array($res); 
    $backupFile = $row['backupFile'];
    $zipFile = $backupLoc . "/" . $backupFile . ".zip";
    $zipSize = filesize($zipFile);

    header('Content-type: application/zip');
    header('Content-Disposition: attachment; filename="' . basename($zipFile). '"'); 
    ob_end_flush();
    readfile($zipFile);
    exit;
    die();

Answer 1

这是 download.php 文件导致的问题，这里是解决方案。这是进行 OB CLEAN 而不是冲洗

    ///echo "<div style='padding: 50px;'>Please Wait .....</div>";
    $fileID = $_GET['id'];
    $backupLoc = "backups/";
    $sql = "SELECT * FROM backups WHERE id = '" . addslashes($fileID) .  "' LIMIT 1";
    $res = mysql_query($sql);
    $row = mysql_fetch_array($res); 
    $backupFile = $row['backupFile'];
    $zipFile = $backupLoc . "/" . $backupFile . ".zip";
    $zipSize = filesize($zipFile);

    header('Content-type: application/zip');
    header('Content-Disposition: attachment; filename="' . basename($zipFile). '"'); 
    //ob_end_flush();
    ob_end_clean(); 
    readfile($zipFile);
    exit;
    die();