通过固定的给定行查找并替换具有重复数字的数组的行

Question

我的矩阵有重复数字的行.我想找到那些行并用虚拟行替换它们,以便保持矩阵的行数不变.

Dummy_row = [1 2 3]

(5x3)矩阵A.

A = [2 3 6;
     4 7 4;
     8 7 2;
     1 3 1;
     7 8 2]

(5x3)Matrix new_A

new_A = [2 3 6;
         1 2 3;
         8 7 2;
         1 2 3;
         7 8 2]

我尝试了以下删除了重复数字的行.

y = [1 2 3]
w = sort(A,2)
v = all(diff(t,1,2)~=0|w(:,1:2)==0,2)  %  When v is zero, the row has repeated numbers
z = A(w,:)

你能帮忙吗？

Answer 1

bsxfun基于解决方案 -

%// Create a row mask of the elements that are to be edited
mask = any(sum(bsxfun(@eq,A,permute(A,[1 3 2])),2)>1,3);

%// Setup output variable and set to-be-edited rows as copies of [1 2 3]
new_A = A;
new_A(mask,:) = repmat(Dummy_row,sum(mask),1)

代码运行-

A =
     2     3     6
     4     7     4
     8     7     2
     1     3     1
     7     8     2
new_A =
     2     3     6
     1     2     3
     8     7     2
     1     2     3
     7     8     2