时间戳速度
1. 2014-12-04 12:30:10 104,105,105,106,106,106,99,90
2. 2014-12-04 12:32:19 86,86,87,88,88,89,90,92,93,95,97,100,102,104,1...
3. 2014-12-04 12:32:58 110,110,110,110,110,110,110,110,110,110,110,10..
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DatetimeIndex: 24 个条目,2014-12-04 12:30:10 到 2014-12-04 12:29:13 数据列(共 1 列):速度 24 个非空对象
我想像这样传输 DataFrame:
timestamp speeds
1. 2014-12-04 12:30:10 104
2. 2014-12-04 12:30:11 105
3. 2014-12-04 12:30:12 105
4. ....
5. 2014-12-04 12:32:17 90
6. 2014-12-04 12:32:18 88 (resample and fill the timestamp and the mean speed value)
7. 2014-12-04 12:32:19 86
8. 2014-12-04 12:32:20 86
9. 2014-12-04 12:32:21 87
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有简单的功能可以做到这一点吗?或者只逐行迭代并解析字段?
不确定 pandas,但你可以用纯 python 来完成。很难,我不知道你所说的“(重新采样并填充时间戳和平均速度值)”是什么意思。但如果没有这个,你可以如下:
from datetime import datetime, timedelta
in_s = ["2014-12-04 12:30:10 104,105,105,106,106,106,99,90",
"2014-12-04 12:32:19 86,86,87,88,88,89,90,92,93,95,97,100,102,104",
"2014-12-04 12:32:58 110,110,110,110,110,110,110,110,110,110,110"]
for row in in_s:
date_str,time_str, entries_str = row.split()
#print(a_date,a_time, entries)
a_time = datetime.strptime(time_str, "%H:%M:%S")
for e in entries_str.split(','):
print(date_str, datetime.strftime(a_time, "%H:%M:%S"), e)
a_time = a_time + timedelta(seconds=1)
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这导致:
2014-12-04 12:30:10 104
2014-12-04 12:30:11 105
2014-12-04 12:30:12 105
2014-12-04 12:30:13 106
2014-12-04 12:30:14 106
2014-12-04 12:30:15 106
2014-12-04 12:30:16 99
2014-12-04 12:30:17 90
2014-12-04 12:32:19 86
2014-12-04 12:32:20 86
2014-12-04 12:32:21 87
2014-12-04 12:32:22 88
2014-12-04 12:32:23 88
2014-12-04 12:32:24 89
2014-12-04 12:32:25 90
2014-12-04 12:32:26 92
2014-12-04 12:32:27 93
2014-12-04 12:32:28 95
2014-12-04 12:32:29 97
2014-12-04 12:32:30 100
2014-12-04 12:32:31 102
2014-12-04 12:32:32 104
2014-12-04 12:32:58 110
2014-12-04 12:32:59 110
2014-12-04 12:33:00 110
2014-12-04 12:33:01 110
2014-12-04 12:33:02 110
2014-12-04 12:33:03 110
2014-12-04 12:33:04 110
2014-12-04 12:33:05 110
2014-12-04 12:33:06 110
2014-12-04 12:33:07 110
2014-12-04 12:33:08 110
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