将List转换为Set,然后获得具有相同顺序的List

Uma*_*air 0 python list python-3.x

我有一个包含一些重复值的List,

myList = [2,7,6,6,9,2,4,2]
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我想获得独特的元素

myList  = set(myList)
myListisBack = list(myList)
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但问题是我得到了

[9, 2, 4, 6, 7]
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如何获得相同订单的列表

[2,7,6,9,4]
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fal*_*tru 6

set是一个无序的集合.使用collections.OrderedDict.fromkeys保持顺序:

>>> myList = [2,7,6,6,9,2,4,2]
>>> import collections
>>> list(collections.OrderedDict.fromkeys(myList))
[2, 7, 6, 9, 4]
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