Dan*_*ach 5 .net c# transactionscope task-parallel-library async-await
除了 .NET 4.5.1 之外,TransactionScope 上还有一个新选项,可以使用异步流。这允许编写以下客户端代码
using(var txt = new TransactionScope(..., TransactionScopeAsyncFlowOption.Enabled)
{
await sender.SendAsync();
}
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到目前为止,一切都很好。但是当我需要实现一个易失性的 IEnlistmentNotification 时,我很难做到这一点。让我们想象一下以下场景,假设:我的底层基础设施从下到上完全异步
public class MessageSender : ISendMessages
{
public async Task SendAsync(TransportMessage message, SendOptions options)
{
await sender.SendAsync(message);
}
}
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所以我想要实现的是引入一个像这样的易失性IEnlistmentNotification:
internal class SendResourceManager : IEnlistmentNotification
{
private readonly Func<Task> onCommit;
public SendResourceManager(Func<Task> onCommit)
{
this.onCommit = onCommit;
}
public void Prepare(PreparingEnlistment preparingEnlistment)
{
preparingEnlistment.Prepared();
}
public void Commit(Enlistment enlistment)
{
await this.onCommit();
enlistment.Done();
}
public void Rollback(Enlistment enlistment)
{
enlistment.Done();
}
public void InDoubt(Enlistment enlistment)
{
enlistment.Done();
}
}
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和新的发件人
public class MessageSender : ISendMessages
{
public async Task SendAsync(TransportMessage message, SendOptions options)
{
// Dirty: Let's assume Transaction.Current is never null
Transaction.Current.EnlistVolatile(new SendResourceManager(async () => { await sender.SendAsync(message) }));
}
}
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注意:当然这段代码不能编译。这需要我将提交方法声明为 async void。这太棒了。
所以我的问题是:如何编写一个可以在内部等待异步操作的登记?
只要EnlistVolatile不是 CPU 密集型耗时操作,您就可以使用Task以下方法创建基于精简的包装器:EnlistVolatileTask.FromResult
public static class TranscationExtensions
{
public static Task EnlistVolatileAsync(this Transaction transaction,
IEnlistmentNotification
enlistmentNotification,
EnlistmentOptions enlistmentOptions)
{
return Task.FromResult(transaction.EnlistVolatile
(enlistmentNotification,
enlistmentOptions));
}
}
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然后在你的方法中使用它:
public class MessageSender : ISendMessages
{
public Task SendAsync(TransportMessage message, SendOptions options)
{
return Transaction.Current.EnlistVolatileAsync
(new SendResourceManager(async () =>
{ await sender.SendAsync(message) }));
}
}
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可以在您的调用堆栈中等待更高的位置:
MessageSender sender = new MessageSender();
await sender.SendAsync(message, options);
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